238 92 M gives xy N + 2 4 2 He x y N gives A B L + 2 bita ^+ The number of neutrons in the element L is

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Consider the following nuclear reactions , 238 92 M gives xy N + 2 4 2 He x y N gives A B L + 2 bita ^+ The number of neutrons in the element L is
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Feb
Consider the following nuclear reactions , 238 92 M gives xy N + 2 4 2 He x y N gives A B L + 2 bita ^+ The number of neutrons in the element L is 238 92 M gives xy N + 2 4 2 He x y N gives A B L [...]
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