20 mL of 0.1 M weak acid HA(Ka=10^−5) is mixed with solution of 10 mL of 0.3 M HCl and 10 mL. of 0.1 M NaOH. Find the value of [A−]/([HA]+[A^(-)])` in the resulting solution :

Sahay Sir > Question Answers > 20 mL of 0.1 M weak acid HA(Ka=10^−5) is mixed with solution of 10 mL of 0.3 M HCl and 10 mL. of 0.1 M NaOH. Find the value of [A−]/([HA]+[A^(-)])` in the resulting solution :
20 mL of 0.1 M weak acid HA(Ka=10^−5) is mixed with solution of 10 mL of 0.3 M HCl and 10 mL. of 0.1 M NaOH. Find the value of [A−]/([HA]+[A^(-)])` in the resulting solution :
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Nov
20 mL of 0.1 M weak acid HA(Ka=10^−5) is mixed with solution of 10 mL of 0.3 M HCl and 10 mL. of 0.1 M NaOH. Find the value of [A−]/([HA]+[A^(-)])` in the resulting solution : 20 mL of 0.1 M weak acid HA(Ka=10^−5) is mixed with solution of 10 mL of 0.3 M HCl [...]
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Tags: 20 mL of 0.1 M weak acid HA(Ka=10^−5) is mixed with solution of 10 mL of 0.3 M HCl and 10 mL. of 0.1 M NaOH. Find the value of [A−]/([HA]+[A^(-)])` in the resulting solution : ,