2 m ) respectively. The resultant electric field due to the two dipoles at the point (1 m
Sahay Sir > Question Answers > 2 m ) respectively. The resultant electric field due to the two dipoles at the point (1 m
A ring of radius R is placed in the plane with its centre at origin and its axis along the x -axis and having uniformly distributed positive charge. A ring of radius r (<<R ) and coaxial with the larger ring is moving along the axis with constant velocity, then the variation of electrical flux (phi) passing through the smaller ring with position will be best represented by
17
Sep
A ring of radius R is placed in the plane with its centre at origin and its axis along the x -axis and having uniformly distributed positive charge. A ring of radius r (<<R ) and coaxial with the larger ring is moving along the axis with constant velocity, then the variation of electrical flux [...]
A positive point charge Q is placed (on the axis of disc) at a distance of 4 R . Above the centre of a disc of radius R as shown in situation I. the magnitude of electric flux through the disc is (ϕ). Now a hemis pherical shell of radius R is placed over the disc. such that it forms a closed surface as shown in situation II. The flux through the curved suface in situation II taking direction of area vector along outward normal as positive is
17
Sep
A positive point charge Q is placed (on the axis of disc) at a distance of 4 R . Above the centre of a disc of radius R as shown in situation I. the magnitude of electric flux through the disc is (ϕ). Now a hemis pherical shell of radius R is placed over the [...]
A point charge q is placed near hemisperical surface without base, cylindrical surface with one end open sperical surface and hemispherical surface with base as shown in the figure in (a) (b) (c) and (d) respectively In which of the following cases m the flux crossing through the surface is zero ?
17
Sep
A point charge q is placed near hemisperical surface without base, cylindrical surface with one end open sperical surface and hemispherical surface with base as shown in the figure in (a) (b) (c) and (d) respectively In which of the following cases m the flux crossing through the surface is zero ? 0 ) and [...]
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0 ) and ( 1m ,
0) is ,
2 m ) respectively. The resultant electric field due to the two dipoles at the point (1 m ,
A point charge q is placed near hemisperical surface without base ,
At each point on the surface of the cube shown in the figure ,
Two short dipoles pk and p/2 k are located at ( 0 ,
At each point on the surface of the cube shown in the figure, the electric field is parllel to the z- axis. The length of each edge of the cube is 3.0 m on the bottom face it is E→=34kˆN/C and on the bottom face it is E→=20kˆN/C . Find the net flux contained within the cube.
17
Sep
At each point on the surface of the cube shown in the figure, the electric field is parllel to the z- axis. The length of each edge of the cube is 3.0 m on the bottom face it is E→=34kˆN/C and on the bottom face it is E→=20kˆN/C . Find the net flux contained within [...]
An electric field given by E = 4.0i -3.0 (y^2 +2.0 ) j pierces a Gaussian cube of edgr length 2 m and positioned as shown in the figure. ( The magnitude E is in newtons per coulomb and the position x is in meters.) What is the electric flux through the (a) top face, (b) what is the net electric flux through the cube ?
17
Sep
An electric field given by E = 4.0i -3.0 (y^2 +2.0 ) j pierces a Gaussian cube of edgr length 2 m and positioned as shown in the figure. ( The magnitude E is in newtons per coulomb and the position x is in meters.) What is the electric flux through the (a) top face, [...]
Two short dipoles pk and p/2 k are located at ( 0,0,0 ) and ( 1m, 0, 2 m ) respectively. The resultant electric field due to the two dipoles at the point (1 m, 0, 0 ) is
17
Sep
Two short dipoles pk and p/2 k are located at ( 0,0,0 ) and ( 1m, 0, 2 m ) respectively. The resultant electric field due to the two dipoles at the point (1 m, 0, 0 ) is 0 ) and ( 1m 0) is 2 m ) respectively. The resultant electric field due [...]