10. Substituting x = – 3 in (b) x^2 – 5x + 4 gives (– 3)^2– 5( – 3)+4 = 9–15+4 = – 2

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10. Substituting x = – 3 in (b) x^2 – 5x + 4 gives (– 3)^2– 5( – 3)+4 = 9–15+4 = – 2
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10. Substituting x = – 3 in (b) x^2 – 5x + 4 gives (– 3)^2– 5( – 3)+4 = 9–15+4 = – 2 10. Substituting x = – 3 in (b) x^2 – 5x + 4 gives (– 3)^2– 5( – 3)+4 = 9–15+4 = – 2 October 13, 2020 Category: Chapter 14 - [...]
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