10. Substituting x = – 3 in (a) x^2 + 5x + 4 gives (– 3)^2+5(– 3)+4 = 9+2+4 = 15

Sahay Sir > Question Answers > 10. Substituting x = – 3 in (a) x^2 + 5x + 4 gives (– 3)^2+5(– 3)+4 = 9+2+4 = 15
10. Substituting x = – 3 in (a) x^2 + 5x + 4 gives (– 3)^2+5(– 3)+4 = 9+2+4 = 15
13
Oct
10. Substituting x = – 3 in (a) x^2 + 5x + 4 gives (– 3)^2+5(– 3)+4 = 9+2+4 = 15 10. Substituting x = – 3 in (a) x^2 + 5x + 4 gives (– 3)^2+5(– 3)+4 = 9+2+4 = 15 October 13, 2020 Category: Chapter 14 - Factorisation , Maths , NCERT Class [...]
Posted in: Chapter 14 - Factorisation , Maths , NCERT Class 8 ,
Tags: 10. Substituting x = – 3 in (a) x^2 + 5x + 4 gives (– 3)^2+5(– 3)+4 = 9+2+4 = 15 ,
10. Substituting x = – 3 in (a) x^2 + 5x + 4 gives (– 3)^2+5(– 3)+4 = 9+2+4 = 15
13
Oct
10. Substituting x = – 3 in (a) x^2 + 5x + 4 gives (– 3)^2+5(– 3)+4 = 9+2+4 = 15 10. Substituting x = – 3 in (a) x^2 + 5x + 4 gives (– 3)^2+5(– 3)+4 = 9+2+4 = 15 October 13, 2020 Category: Chapter 14 - Factorisation , Maths , NCERT Class [...]
Posted in: Chapter 14 - Factorisation , Maths , NCERT Class 8 ,
Tags: 10. Substituting x = – 3 in (a) x^2 + 5x + 4 gives (– 3)^2+5(– 3)+4 = 9+2+4 = 15 ,