1. ΔABC and ΔDBC are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC (see Fig. 7.39). If AD is extended to intersect BC at P

Sahay Sir > Question Answers > 1. ΔABC and ΔDBC are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC (see Fig. 7.39). If AD is extended to intersect BC at P
1. ΔABC and ΔDBC are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC (see Fig. 7.39). If AD is extended to intersect BC at P, show that (i) ΔABD =~ ΔACD (ii) ΔABP =~ ΔACP (iii) AP bisects angle A as well as angle D. (iv) AP is the perpendicular bisector of BC.
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Oct
1. ΔABC and ΔDBC are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC (see Fig. 7.39). If AD is extended to intersect BC at P, show that (i) ΔABD =~ ΔACD (ii) ΔABP =~ ΔACP (iii) AP bisects angle A as well as [...]
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Tags: 1. ΔABC and ΔDBC are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC (see Fig. 7.39). If AD is extended to intersect BC at P , show that (i) ΔABD =~ ΔACD (ii) ΔABP =~ ΔACP (iii) AP bisects angle A as well as angle D. (iv) AP is the perpendicular bisector of BC. ,