1. In a ∆ PQR

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1. In a ∆ PQR, PR^2 – PQ^2 = QR^2 and M is a point on side PR such that QM ⊥ PR. Prove that QM^2 = PM × MR.
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Jul
1. In a ∆ PQR, PR^2 – PQ^2 = QR^2 and M is a point on side PR such that QM ⊥ PR. Prove that QM^2 = PM × MR. 1. In a ∆ PQR PR^2 – PQ^2 = QR^2 and M is a point on side PR such that QM ⊥ PR. Prove that [...]
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