1 g mole of CaC03 is enclosed in 5 L container CaC03(s)−−>CaO(s)+C02(g) Kp=1.16 at 1073 K then per cent dissociation of CaC03 is
Sahay Sir > Question Answers > 1 g mole of CaC03 is enclosed in 5 L container CaC03(s)−−>CaO(s)+C02(g) Kp=1.16 at 1073 K then per cent dissociation of CaC03 is
For the reaction, 1 g mole of CaC03 is enclosed in 5 L container CaC03(s)−−>CaO(s)+C02(g) Kp=1.16 at 1073 K then per cent dissociation of CaC03 is 1 g mole of CaC03 is enclosed in 5 L container CaC03(s)−−>CaO(s)+C02(g) Kp=1.16 at 1073 K then per cent dissociation of CaC03 is For the reaction November 16, 2020 [...]