0.53% of the incident photons eject photo electrons. Find the number of photo-electrons emitted per second and their minimum and maximum energies (in eV). Take 1 eV = 1.6 x 10^-19 J.

Sahay Sir > Question Answers > 0.53% of the incident photons eject photo electrons. Find the number of photo-electrons emitted per second and their minimum and maximum energies (in eV). Take 1 eV = 1.6 x 10^-19 J.
When a beam of 10.6 eV photons of intensity 2.0 W/m^2 falls on a platinum surface of area 1.0 x 10^-4 m^2 and work function 5.6 eV, 0.53% of the incident photons eject photo electrons. Find the number of photo-electrons emitted per second and their minimum and maximum energies (in eV). Take 1 eV = 1.6 x 10^-19 J.
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Sep
When a beam of 10.6 eV photons of intensity 2.0 W/m^2 falls on a platinum surface of area 1.0 x 10^-4 m^2 and work function 5.6 eV, 0.53% of the incident photons eject photo electrons. Find the number of photo-electrons emitted per second and their minimum and maximum energies (in eV). Take 1 eV = [...]
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Tags: 0.53% of the incident photons eject photo electrons. Find the number of photo-electrons emitted per second and their minimum and maximum energies (in eV). Take 1 eV = 1.6 x 10^-19 J. , When a beam of 10.6 eV photons of intensity 2.0 W/m^2 falls on a platinum surface of area 1.0 x 10^-4 m^2 and work function 5.6 eV ,