Question Answers
Sahay Sir > Question Answers
Producer gas is a mixture of (a) CO and N2 (b) CO2 and H2 (c) N2 and O2 (d) CH4 and N2
12
Dec
Producer gas is a mixture of (a) CO and N2 (b) CO2 and H2 (c) N2 and O2 (d) CH4 and N2 Producer gas is a mixture of (a) CO and N2 (b) CO2 and H2 (c) N2 and O2 (d) CH4 and N2 December 12, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma [...]
The product obtained on reaction of C2H5Cl with hydrogen over palladium carbon is (a) C3H8 (b) C4H10
12
Dec
The product obtained on reaction of C2H5Cl with hydrogen over palladium carbon is (a) C3H8 (b) C4H10 The product obtained on reaction of C2H5Cl with hydrogen over palladium carbon is (a) C3H8 (b) C4H10 December 12, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
Octane number can be changed by (a) Isomerisation (b) Alkylation (c) Cyclisation (d) All of these
12
Dec
Octane number can be changed by (a) Isomerisation (b) Alkylation (c) Cyclisation (d) All of these Octane number can be changed by (a) Isomerisation (b) Alkylation (c) Cyclisation (d) All of these December 12, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
PA and PB are the vapour pressure of pure liquid components A and B respectively of an ideal binary solution. If xA represents the mole fraction of component A, the total pressure of the solution will be :
12
Dec
PA and PB are the vapour pressure of pure liquid components A and B respectively of an ideal binary solution. If xA represents the mole fraction of component A, the total pressure of the solution will be : PA and PB are the vapour pressure of pure liquid components A and B respectively of an [...]
A solution has 1 : 4 mole ratio of pentane to hexane . The vapour pressure of pure hydrocarbons at 20∘Care 440 mm Hg for pentane and 120 mm Hg for hexane .The mole fraction of pentane in the vapour phase would be
12
Dec
A solution has 1 : 4 mole ratio of pentane to hexane . The vapour pressure of pure hydrocarbons at 20∘Care 440 mm Hg for pentane and 120 mm Hg for hexane .The mole fraction of pentane in the vapour phase would be For 0.1 M solution the colligative property will follow the order (a) [...]
Vapour pressure of chloroform ( CHCl3 ) and dichloromethane (CH2CL2 ) at 25 degree C are 200 mm Hg and 415 mm Hg respectively. Vapour pressure of the solution obtained by mixing 25.5 g of CHCl 3 and 40 g of CH 2Cl 2 at the same temperature will be: [Molecular mass of CHCl 3 = 119.5 g/mol and molecular mass of CH 2 Cl 2 =85 g/ mol ]
12
Dec
Vapour pressure of chloroform ( CHCl3 ) and dichloromethane (CH2CL2 ) at 25 degree C are 200 mm Hg and 415 mm Hg respectively. Vapour pressure of the solution obtained by mixing 25.5 g of CHCl 3 and 40 g of CH 2Cl 2 at the same temperature will be: [Molecular mass of CHCl [...]
As the number of carbon atoms in a chain increases the boiling point of alkanes (a) Increases (b) Decreases (c) Remains same
12
Dec
As the number of carbon atoms in a chain increases the boiling point of alkanes (a) Increases (b) Decreases (c) Remains same As the number of carbon atoms in a chain increases the boiling point of alkanes (a) Increases (b) Decreases (c) Remains same December 12, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma [...]
CH4 is formed when (a) Sodium acetate is heated with sodalime (b) Iodomethane is reduced
12
Dec
CH4 is formed when (a) Sodium acetate is heated with sodalime (b) Iodomethane is reduced CH4 is formed when (a) Sodium acetate is heated with sodalime (b) Iodomethane is reduced December 12, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
An aqueous solution is 1.00 molal in KI. Which change will cause the vapour pressure of the solution to increase
12
Dec
An aqueous solution is 1.00 molal in KI. Which change will cause the vapour pressure of the solution to increase An aqueous solution is 1.00 molal in KI. Which change will cause the vapour pressure of the solution to increase December 12, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
On monochlorination of n-pentane, the number of straight chain isomers formed is (a) 4 (b) 3 (c) 2 (d) 1
12
Dec
On monochlorination of n-pentane, the number of straight chain isomers formed is (a) 4 (b) 3 (c) 2 (d) 1 On monochlorination of n-pentane the number of straight chain isomers formed is (a) 4 (b) 3 (c) 2 (d) 1 December 12, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,