Question Answers
Sahay Sir > Question Answers
The area of the figure formed by joining the mid-points of the adjacent sides of a rhombus with diagonals 12 cm and 16 cm is
01
Jul
The area of the figure formed by joining the mid-points of the adjacent sides of a rhombus with diagonals 12 cm and 16 cm is The area of the figure formed by joining the mid-points of the adjacent sides of a rhombus with diagonals 12 cm and 16 cm is July 1, 2021 Category: Chapter [...]
10. In Fig. 9.27, ABCD and AEFD are two parallelograms. Prove that ar (PEA) = ar (QFD) [Hint: Join PD].
01
Jul
10. In Fig. 9.27, ABCD and AEFD are two parallelograms. Prove that ar (PEA) = ar (QFD) [Hint: Join PD]. 10. In Fig. 9.27 ABCD and AEFD are two parallelograms. Prove that ar (PEA) = ar (QFD) [Hint: Join PD]. July 1, 2021 Category: Chapter 9 - Areas of Parallelogram and Triangles , Maths , [...]
9. In Fig. 9.26, X and Y are the mid-points of AC and AB respectively, QP || BC and CYQ and BXP are straight lines. Prove that ar (ABP) = ar (ACQ).
01
Jul
9. In Fig. 9.26, X and Y are the mid-points of AC and AB respectively, QP || BC and CYQ and BXP are straight lines. Prove that ar (ABP) = ar (ACQ). 9. In Fig. 9.26 QP || BC and CYQ and BXP are straight lines. Prove that ar (ABP) = ar (ACQ). X and [...]
8. If the medians of a ∆ ABC intersect at G, show that ar (AGB) = ar (AGC) = ar (BGC) = 1/3 ar (ABC)
01
Jul
8. If the medians of a ∆ ABC intersect at G, show that ar (AGB) = ar (AGC) = ar (BGC) = 1/3 ar (ABC) 8. If the medians of a ∆ ABC intersect at G show that ar (AGB) = ar (AGC) = ar (BGC) = 1/3 ar (ABC) July 1, 2021 Category: Chapter [...]
7. In Fig. 9.25, ABCDE is any pentagon. BP drawn parallel to AC meets DC produced at P and EQ drawn parallel to AD meets CD produced at Q. Prove that ar (ABCDE) = ar (APQ)
01
Jul
7. In Fig. 9.25, ABCDE is any pentagon. BP drawn parallel to AC meets DC produced at P and EQ drawn parallel to AD meets CD produced at Q. Prove that ar (ABCDE) = ar (APQ) 7. In Fig. 9.25 ABCDE is any pentagon. BP drawn parallel to AC meets DC produced at P and [...]
6. In ∆ ABC, if L and M are the points on AB and AC, respectively such that LM || BC. Prove that ar (LOB) = ar (MOC)
01
Jul
6. In ∆ ABC, if L and M are the points on AB and AC, respectively such that LM || BC. Prove that ar (LOB) = ar (MOC) 6. In ∆ ABC if L and M are the points on AB and AC respectively such that LM || BC. Prove that ar (LOB) = ar [...]
5. ABCD is a trapezium in which AB || DC, DC = 30 cm and AB = 50 cm. If X and Y are, respectively the mid-points of AD and BC, prove that ar (DCYX) = 7/9 ar (XYBA)
01
Jul
5. ABCD is a trapezium in which AB || DC, DC = 30 cm and AB = 50 cm. If X and Y are, respectively the mid-points of AD and BC, prove that ar (DCYX) = 7/9 ar (XYBA) 5. ABCD is a trapezium in which AB || DC DC = 30 cm and AB [...]
4. In Fig. 9.24, CD || AE and CY || BA. Prove that ar (CBX) = ar (AXY)
01
Jul
4. In Fig. 9.24, CD || AE and CY || BA. Prove that ar (CBX) = ar (AXY) 4. In Fig. 9.24 CD || AE and CY || BA. Prove that ar (CBX) = ar (AXY) July 1, 2021 Category: Chapter 9 - Areas of Parallelogram and Triangles , Maths , NCERT Class 9 ,
3. The medians BE and CF of a triangle ABC intersect at G. Prove that the area of ∆ GBC = area of the quadrilateral AFGE.
01
Jul
3. The medians BE and CF of a triangle ABC intersect at G. Prove that the area of ∆ GBC = area of the quadrilateral AFGE. 3. The medians BE and CF of a triangle ABC intersect at G. Prove that the area of ∆ GBC = area of the quadrilateral AFGE. July 1, 2021 [...]
2. The diagonals of a parallelogram ABCD intersect at a point O. Through O, a line is drawn to intersect AD at P and BC at Q. Show that PQ divides the parallelogram into two parts of equal area.
01
Jul
2. The diagonals of a parallelogram ABCD intersect at a point O. Through O, a line is drawn to intersect AD at P and BC at Q. Show that PQ divides the parallelogram into two parts of equal area. 2. The diagonals of a parallelogram ABCD intersect at a point O. Through O a line [...]