Question Answers
Sahay Sir > Question Answers
A disc of mass m has a charge Q distributed on its surface. It is rotating about an XX’ with a angular velocity omega. The force acting on the disc is
25
Aug
A disc of mass m has a charge Q distributed on its surface. It is rotating about an XX’ with a angular velocity omega. The force acting on the disc is A disc of mass m has a charge Q distributed on its surface. It is rotating about an XX' with a angular velocity omega. [...]
a current i=5amp flows through a thin wire as shown in the figure. find
25
Aug
a current i=5amp flows through a thin wire as shown in the figure. find a current i=5amp flows through a thin wire as shown in the figure. find August 25, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
In a SHM, when the displacement is one half the amplitude, what fraction of the total energy is kinetic?
25
Aug
In a SHM, when the displacement is one half the amplitude, what fraction of the total energy is kinetic? In a SHM what fraction of the total energy is kinetic? when the displacement is one half the amplitude August 25, 2020 Category: Chapter 15 - SHM , NEET Last 32 Years Solved 1988 - 2019 [...]
A linear harmonic oscillator of force constant 2×10^6 N/m and amplitude 0.01 m has a total mechanical energy of 160 J. Its
25
Aug
A linear harmonic oscillator of force constant 2×10^6 N/m and amplitude 0.01 m has a total mechanical energy of 160 J. Its A linear harmonic oscillator of force constant 2×10^6 N/m and amplitude 0.01 m has a total mechanical energy of 160 J. Its August 25, 2020 Category: Chapter 15 - SHM , NEET Last [...]
In an SHM, restoring force is F=−kx, where k is force constant, x is displacement and A is the amplitude of motion, then the total energy depends upon
25
Aug
In an SHM, restoring force is F=−kx, where k is force constant, x is displacement and A is the amplitude of motion, then the total energy depends upon In an SHM restoring force is F=−kx then the total energy depends upon where k is force constant x is displacement and A is the amplitude of [...]
The displacement of particle between maximum potential energy position and maximum kinetic energy position in simple harmonic motion is
25
Aug
The displacement of particle between maximum potential energy position and maximum kinetic energy position in simple harmonic motion is The displacement of particle between maximum potential energy position and maximum kinetic energy position in simple harmonic motion is August 25, 2020 Category: Chapter 15 - SHM , NEET Last 32 Years Solved 1988 - 2019 [...]
A particle of mass m oscillates with simple harmonic motion between points x1 and x2, the equilibrium position being O. Its potential energy is plotted. It will be as given below in the graph:
25
Aug
A particle of mass m oscillates with simple harmonic motion between points x1 and x2, the equilibrium position being O. Its potential energy is plotted. It will be as given below in the graph: A particle of mass m oscillates with simple harmonic motion between points x1 and x2 the equilibrium position being O. Its [...]
In a certain region of space, there exists a uniform and constant electric field of magnitude E along the positive y-axis of a coordinate system. A charged particle of mass m and charge -q (qgt0) is projected form the origin with speed 2v at an angle of 60^@ with the positive x-axis in x-y plane. When the x-coordinate of particle becomes sqrt3mv^2//qE a uniform and constant magnetic. field of strength B is also switched on along positive y-axis. z-coordinate of the particle as a function of time after the magnetic field is switched on is
25
Aug
In a certain region of space, there exists a uniform and constant electric field of magnitude E along the positive y-axis of a coordinate system. A charged particle of mass m and charge -q (qgt0) is projected form the origin with speed 2v at an angle of 60^@ with the positive x-axis in x-y plane. [...]
The potential energy of a simple harmonic oscillator when the particle is half way to its end point is
25
Aug
The potential energy of a simple harmonic oscillator when the particle is half way to its end point is The potential energy of a simple harmonic oscillator when the particle is half way to its end point is August 25, 2020 Category: Chapter 15 - SHM , NEET Last 32 Years Solved 1988 - 2019 [...]
A insulated square frame ABCD of side a is able to rotate about one of its side taken as positive z-axis. A magnetic field B is present in the region given by vecB=B_(0)hatj. A small block of mass m and charge q movable along side CB is initially near C, when frame lies in x-z plane. Now, frame is rotated by constant angular velocity omega about z-axis. Whole system lies in gravity free space. If after time t block reaches point B, find B_(0) in terms of t.
25
Aug
A insulated square frame ABCD of side a is able to rotate about one of its side taken as positive z-axis. A magnetic field B is present in the region given by vecB=B_(0)hatj. A small block of mass m and charge q movable along side CB is initially near C, when frame lies in x-z [...]