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In Ohm’s law experiment, potential drop across a resistance was measured as v=5.0 volt and current was measured as i=2.00amp. Find the maximum permissible error in resistance.
31
Aug
In Ohm’s law experiment, potential drop across a resistance was measured as v=5.0 volt and current was measured as i=2.00amp. Find the maximum permissible error in resistance. In Ohm's law experiment potential drop across a resistance was measured as v=5.0 volt and current was measured as i=2.00amp. Find the maximum permissible error in resistance. August [...]
(a) Find the field intensity if potential V = -kxy (k >0 ). (b) draw the field pattern of tthe field.
31
Aug
(a) Find the field intensity if potential V = -kxy (k >0 ). (b) draw the field pattern of tthe field. (a) Find the field intensity if potential V = -kxy (k >0 ). (b) draw the field pattern of tthe field. August 31, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP [...]
If the measured value of resistance R = 1.05 Omega, wire diameter d = 0.60 mm , and length l = 75.3 cm, then find the maximum permissible error in resistivity
31
Aug
If the measured value of resistance R = 1.05 Omega, wire diameter d = 0.60 mm , and length l = 75.3 cm, then find the maximum permissible error in resistivity and length l = 75.3 cm If the measured value of resistance R = 1.05 Omega then find the maximum permissible error in resistivity [...]
Determine the electric field strength vector if the potential of this field depends on x, coordinates as (a) V = a(x^2—y^2) (b) V = axy where, a is a constant.
31
Aug
Determine the electric field strength vector if the potential of this field depends on x, coordinates as (a) V = a(x^2—y^2) (b) V = axy where, a is a constant. a is a constant. coordinates as (a) V = a(x^2—y^2) (b) V = axy where Determine the electric field strength vector if the potential of [...]
Some equipotential surfaces are shown in figure . What can you say about the magnitude and the direction of the electric field ?
31
Aug
Some equipotential surfaces are shown in figure . What can you say about the magnitude and the direction of the electric field ? Some equipotential surfaces are shown in figure . What can you say about the magnitude and the direction of the electric field ? August 31, 2020 Category: Uncategorised (JEE Advanced Physics by [...]
In resonance tube experiment, the velocity of sound is given by v = 2f0 (l2 – l1 ). We found l1 = 250cm and l2 = 75.0cm. If there is no error in frequency, what will be the maximum permissible error in the speed of sound? (Take f0 = 325Hz)
31
Aug
In resonance tube experiment, the velocity of sound is given by v = 2f0 (l2 – l1 ). We found l1 = 250cm and l2 = 75.0cm. If there is no error in frequency, what will be the maximum permissible error in the speed of sound? (Take f0 = 325Hz) In resonance tube experiment the [...]
If all measurements in an experiment are taken up to the same number of significant figures, then mention two possible reasons for maximum error
31
Aug
If all measurements in an experiment are taken up to the same number of significant figures, then mention two possible reasons for maximum error If all measurements in an experiment are taken up to the same number of significant figures then mention two possible reasons for maximum error August 31, 2020 Category: Uncategorised (JEE Advanced [...]
The distance covered by a body in time (5.0 ± 0.6)s is (40.0 ± 0.4)m. calculate the percentage error in speed of the body
31
Aug
The distance covered by a body in time (5.0 ± 0.6)s is (40.0 ± 0.4)m. calculate the percentage error in speed of the body The distance covered by a body in time (5.0 ± 0.6)s is (40.0 ± 0.4)m. calculate the percentage error in speed of the body August 31, 2020 Category: Uncategorised (JEE Advanced [...]
The potential at any point is given by V = x (y^2−4x^2) . Calculate the cartesian components of the electric field at the point.
31
Aug
The potential at any point is given by V = x (y^2−4x^2) . Calculate the cartesian components of the electric field at the point. The potential at any point is given by V = x (y^2−4x^2) . Calculate the cartesian components of the electric field at the point. August 31, 2020 Category: Uncategorised (JEE Advanced [...]
The electric potential decreases unifromly from 120 V to 80 V as one moves on the x-axis from x=-1 cm to x=+1 cm. The electric field at the origin
31
Aug
The electric potential decreases unifromly from 120 V to 80 V as one moves on the x-axis from x=-1 cm to x=+1 cm. The electric field at the origin The electric potential decreases unifromly from 120 V to 80 V as one moves on the x-axis from x=-1 cm to x=+1 cm. The electric field [...]