Question Answers
Sahay Sir > Question Answers
Solve the problems given in Example 1. x2 – 55x + 750 = 0
04
Oct
Solve the problems given in Example 1. x2 – 55x + 750 = 0 Solve the problems given in Example 1. x2 - 55x + 750 = 0 October 4, 2020 Category: Chapter 4 - Quadratic Equations , Maths , NCERT Class 10 ,
Solve the problems given in Example 1. x2 – 45x + 324 = 0
04
Oct
Solve the problems given in Example 1. x2 – 45x + 324 = 0 Solve the problems given in Example 1. x2 – 45x + 324 = 0 October 4, 2020 Category: Chapter 4 - Quadratic Equations , Maths , NCERT Class 10 ,
Two walls of thickness d 1 and d 2 ,thermal conductivities K 1 and K 2 are in contact.In the steady state if the temperatures at the outer surfaces are T 1 and T 2 , the temperature at the common wall will be
04
Oct
Two walls of thickness d 1 and d 2 ,thermal conductivities K 1 and K 2 are in contact.In the steady state if the temperatures at the outer surfaces are T 1 and T 2 , the temperature at the common wall will be the temperature at the common wall [...]
Two vessels of different materials are similar in size in every respect. The same quantity of ice filled in them gets melted in 20 minutes and 30 minutes respectively. The ratio of thermal conductivities of the materials is
04
Oct
Two vessels of different materials are similar in size in every respect. The same quantity of ice filled in them gets melted in 20 minutes and 30 minutes respectively. The ratio of thermal conductivities of the materials is The rate at which the energy conducted upward is October 4, 2020 Category: Uncategorised (JEE Advanced Physics [...]
Find the roots of the following quadratic equations by factorisation: 100x^2 − 20x + 1 = 0
04
Oct
Find the roots of the following quadratic equations by factorisation: 100x^2 − 20x + 1 = 0 Find the roots of the following quadratic equations by factorisation: 100x^2 − 20x + 1 = 0 October 4, 2020 Category: Chapter 4 - Quadratic Equations , Maths , NCERT Class 10 ,
The thermal conductivity of a material in CGS system is 0.4. In steady state, the rtate of flow of heat is 10 cal/sec-cm^2. Then the thermal gradient will be…………
04
Oct
The thermal conductivity of a material in CGS system is 0.4. In steady state, the rtate of flow of heat is 10 cal/sec-cm^2. Then the thermal gradient will be………… the rtate of flow of heat is 10 cal/sec-cm^2. Then the thermal gradient will be............ The thermal conductivity of a material in CGS system is 0.4. [...]
Find the roots of the following quadratic equations by factorisation: 2x^2 – x + 1/8 = 0
04
Oct
Find the roots of the following quadratic equations by factorisation: 2x^2 – x + 1/8 = 0 Find the roots of the following quadratic equations by factorisation: 2x^2 - x + 1/8 = 0 October 4, 2020 Category: Chapter 4 - Quadratic Equations , Maths , NCERT Class 10 ,
Find the roots of the following quadratic equations by factorisation: √2x^2 + 7x + 5√2 = 0
04
Oct
Find the roots of the following quadratic equations by factorisation: √2x^2 + 7x + 5√2 = 0 Find the roots of the following quadratic equations by factorisation: √2x^2 + 7x + 5√2 = 0 October 4, 2020 Category: Chapter 4 - Quadratic Equations , Maths , NCERT Class 10 ,
Find the roots of the following quadratic equations by factorisation: 2x^2 + x − 6=0
04
Oct
Find the roots of the following quadratic equations by factorisation: 2x^2 + x − 6=0 Find the roots of the following quadratic equations by factorisation: 2x^2 + x − 6=0 October 4, 2020 Category: Chapter 4 - Quadratic Equations , Maths , NCERT Class 10 ,
At what rate does the top of the tube move downward because of water freezing there?
04
Oct
At what rate does the top of the tube move downward because of water freezing there? At what rate does the top of the tube move downward because of water freezing there? October 4, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,