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A small object of mass 0.5 kg is attached to an end of a mass less 2 m long rope. It is rotated under gravity in a vertical circle with other end of the rope being at the centre of the circle. A small object of mass 0.5 kg is attached to an end of [...]

E is a point on the side AD produced of a parallelogram ABCD and BE intersects CD at F. Show that ΔABE ∼ ΔCFB. E is a point on the side AD produced of a parallelogram ABCD and BE intersects CD at F. Show that ΔABE ∼ ΔCFB. October 4, 2020 Category: Chapter 6 - [...]

When a body is moving vertically up with constant velocity, then match the following. then match the following. When a body is moving vertically up with constant velocity October 4, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,

In the figure, altitudes AD and CE of ΔABC intersect each other at the point P. Show that: (i) ΔAEP ∼ ΔCDP (ii) ΔABD ∼ ΔCBE (iii) ΔAEP ∼ ΔADB (v) ΔPDC ∼ ΔBEC altitudes AD and CE of ΔABC intersect each other at the point P. Show that: (i) ΔAEP ∼ ΔCDP (ii) ΔABD [...]

A man pushes a block of 30 kg along a level floor at a constant speed with a force directed at 45 below the horizontal. If the coefficient of friction is 0.20, then match the following. A man pushes a block of 30 kg along a level floor at a constant speed with a force [...]

In figure, if ΔABE ≅ ΔACD, show that ΔADE ∼ ΔABC. if ΔABE ≅ ΔACD In figure show that ΔADE ∼ ΔABC. October 4, 2020 Category: Chapter 6 - Triangles , Maths , NCERT Class 10 ,

S and T are points on sides PR and QR of triangle PQR such that angle P = angle RTS Show that triangle RPQ ~ triangle RTS. S and T are points on sides PR and QR of triangle PQR such that angle P = angle RTS Show that triangle RPQ ~ triangle RTS. October [...]

In the figure, = QR /QS = QT/PR and ∠1 = ∠ 2 then prove that ∆PQS ~ ∆TQR . = QR /QS = QT/PR and ∠1 = ∠ 2 then prove that ∆PQS ~ ∆TQR . In the figure October 4, 2020 Category: Chapter 6 - Triangles , Maths , NCERT Class 10 ,

Diagonals AC and BD of a trapezium ABCD with AB || DC intersect each other at the point O. Using similarity criterion for two triangles, show that OA/OC = OB/OD. Diagonals AC and BD of a trapezium ABCD with AB || DC intersect each other at the point O. Using similarity criterion for two triangles [...]

In figure, △ODC∼△OBA, ∠BOC = 125 degree and ∠CDO=70 degree. Find ∠DOC, ∠DCO and ∠OAB. ∠BOC = 125 degree and ∠CDO=70 degree. Find ∠DOC ∠DCO and ∠OAB. △ODC∼△OBA In figure October 4, 2020 Category: Chapter 6 - Triangles , Maths , NCERT Class 10 ,