Question Answers
Sahay Sir > Question Answers
In figure, a point source S is placed at a height h above the plane mirror in a medium of refractive index mu. (a) Find the number of images seen for normal view. (b) Find the distance between the images.
05
Oct
In figure, a point source S is placed at a height h above the plane mirror in a medium of refractive index mu. (a) Find the number of images seen for normal view. (b) Find the distance between the images. a point source S is placed at a height h above the plane mirror in [...]
What should be the value of refractive index mu of a glass rod placed in air, so that the light entering through the flat surface of the rod does not cross the curved surface of the rod?
05
Oct
What should be the value of refractive index mu of a glass rod placed in air, so that the light entering through the flat surface of the rod does not cross the curved surface of the rod? so that the light entering through the flat surface of the rod does not cross the curved surface [...]
A slab of water is on the top of a glass slab of refractive index 2. At what angle to the normal must a ray be incident on the top surface of the glass slab so that it is reflected from the bottom
05
Oct
A slab of water is on the top of a glass slab of refractive index 2. At what angle to the normal must a ray be incident on the top surface of the glass slab so that it is reflected from the bottom A slab of water is on the top of a glass slab [...]
A convergent beam is incident on two slabs placed in contact as shown in figure. Where will rays finally converge?
05
Oct
A convergent beam is incident on two slabs placed in contact as shown in figure. Where will rays finally converge? A convergent beam is incident on two slabs placed in contact as shown in figure. Where will rays finally converge? October 5, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
Prove that sin theta – cos theta + 1 / sin theta + cos theta – 1 = 1/sec theta – tan theta, using the identity sec^2 theta = 1 + tan^2 theta.
05
Oct
Prove that sin theta – cos theta + 1 / sin theta + cos theta – 1 = 1/sec theta – tan theta, using the identity sec^2 theta = 1 + tan^2 theta. Prove that sin theta - cos theta + 1 / sin theta + cos theta - 1 = 1/sec theta - tan [...]
Prove that: cot A – cos A / cot A + cos A = cosec A – 1 / cosec A + 1
05
Oct
Prove that: cot A – cos A / cot A + cos A = cosec A – 1 / cosec A + 1 Prove that: cot A - cos A / cot A + cos A = cosec A - 1 / cosec A + 1 October 5, 2020 Category: Chapter 8 - Introduction to [...]
A tank contains three layers of immiscible liquids. The first layer is of water with refractive index 4/3 and thickness 8 cm. The second layer is of oil with refractive index 3/2 and thickness 9 cm
05
Oct
A tank contains three layers of immiscible liquids. The first layer is of water with refractive index 4/3 and thickness 8 cm. The second layer is of oil with refractive index 3/2 and thickness 9 cm A tank contains three layers of immiscible liquids. The first layer is of water with refractive index 4/3 and [...]
Prove that sec a (1-sin a) (sec a + tan a) =1
05
Oct
Prove that sec a (1-sin a) (sec a + tan a) =1 Prove that sec a (1-sin a) (sec a + tan a) =1 October 5, 2020 Category: Chapter 8 - Introduction to Trigonometry , Maths , NCERT Class 10 ,
Express the ratios cos A, tan A and sec A in terms of sin A.
05
Oct
Express the ratios cos A, tan A and sec A in terms of sin A. Express the ratios cos A tan A and sec A in terms of sin A. October 5, 2020 Category: Chapter 8 - Introduction to Trigonometry , Maths , NCERT Class 10 ,
Express cot 85° + cos 75° in terms of trigonometric ratios of angles between 0° and 45°.
05
Oct
Express cot 85° + cos 75° in terms of trigonometric ratios of angles between 0° and 45°. Express cot 85° + cos 75° in terms of trigonometric ratios of angles between 0° and 45°. October 5, 2020 Category: Chapter 8 - Introduction to Trigonometry , Maths , NCERT Class 10 ,