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A diminished image of an object is to be obtained on a screen 1.0 m from it. This can be achieved by appropriately placing
09
Oct
A diminished image of an object is to be obtained on a screen 1.0 m from it. This can be achieved by appropriately placing A diminished image of an object is to be obtained on a screen 1.0 m from it. This can be achieved by appropriately placing October 9, 2020 Category: Uncategorised (JEE Advanced [...]
4.Find the value of: (iii) –4/5÷(–3)
09
Oct
4.Find the value of: (iii) –4/5÷(–3) 4.Find the value of: (iii) –4/5÷(–3) October 9, 2020 Category: Chapter 9 - Rational Numbers , Maths , NCERT Class 7 ,
4.Find the value of: (ii) –3/5÷2
09
Oct
4.Find the value of: (ii) –3/5÷2 4.Find the value of: (ii) –3/5÷2 October 9, 2020 Category: Chapter 9 - Rational Numbers , Maths , NCERT Class 7 ,
4.Find the value of: (i) (–4)÷2/3
09
Oct
4.Find the value of: (i) (–4)÷2/3 4.Find the value of: (i) (–4)÷2/3 October 9, 2020 Category: Chapter 9 - Rational Numbers , Maths , NCERT Class 7 ,
A convex lens cut symmetrically into two equal halves and separated laterally by a distance h as shown in figure. A point object O is placed at a distance 30 cm, from the lens halves.
09
Oct
A convex lens cut symmetrically into two equal halves and separated laterally by a distance h as shown in figure. A point object O is placed at a distance 30 cm, from the lens halves. A convex lens cut symmetrically into two equal halves and separated laterally by a distance h as shown in figure. [...]
Young’s modulus of rubber is 10^4 N/m^2 and area of cross section is 2 cm^2. If force of 2 x 10^5 dyn is applied along its length, then its new length becomes
09
Oct
Young’s modulus of rubber is 10^4 N/m^2 and area of cross section is 2 cm^2. If force of 2 x 10^5 dyn is applied along its length, then its new length becomes then its new length becomes Young's modulus of rubber is 10^4 N/m^2 and area of cross section is 2 cm^2. If force of [...]
3.Find the product: (vi) 3/–5 × -5/3
09
Oct
3.Find the product: (vi) 3/–5 × -5/3 3.Find the product: (vi) 3/–5 × -5/3 October 9, 2020 Category: Chapter 9 - Rational Numbers , Maths , NCERT Class 7 ,
3.Find the product: (v) 3/11 × 2/5
09
Oct
3.Find the product: (v) 3/11 × 2/5 3.Find the product: (v) 3/11 × 2/5 October 9, 2020 Category: Chapter 9 - Rational Numbers , Maths , NCERT Class 7 ,
An elastic material of young’s modulus Y is subjected yo a stress S . The energy stored per unit volume of the material is
09
Oct
An elastic material of young’s modulus Y is subjected yo a stress S . The energy stored per unit volume of the material is An elastic material of young's modulus Y is subjected yo a stress S . The energy stored per unit volume of the material is October 9, 2020 Category: Uncategorised (JEE Advanced [...]
3.Find the product: (iv) 3/7 × (–2/5)
09
Oct
3.Find the product: (iv) 3/7 × (–2/5) 3.Find the product: (iv) 3/7 × (–2/5) October 9, 2020 Category: Chapter 9 - Rational Numbers , Maths , NCERT Class 7 ,