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Light of wavelength lemda = 5890 A falls on a double-slit arrangement having separation d= 0.2 mm. A thin lens of focal length f = 1 m is placed near the slits. The linear
10
Oct
Light of wavelength lemda = 5890 A falls on a double-slit arrangement having separation d= 0.2 mm. A thin lens of focal length f = 1 m is placed near the slits. The linear Light of wavelength lemda = 5890 A falls on a double-slit arrangement having separation d= 0.2 mm. A thin lens of [...]
1.Using laws of exponents, simplify and write the answer in exponential form: (vii) a^4 × b^4
10
Oct
1.Using laws of exponents, simplify and write the answer in exponential form: (vii) a^4 × b^4 1.Using laws of exponents simplify and write the answer in exponential form: (vii) a^4 × b^4 October 10, 2020 Category: Chapter 13 - Exponents and Powers , Maths , NCERT Class 7 ,
The pressure that has to be applied to the ends of a steel wire of length 10 cm to keep its length constant when its temperature is raised by 100∘C is : (For steel Young’s modulus is 2 × 10^11 Nm^−2 and coefficient of thermal expansion is 1.1 × 10^−5 K_1)
10
Oct
The pressure that has to be applied to the ends of a steel wire of length 10 cm to keep its length constant when its temperature is raised by 100∘C is : (For steel Young’s modulus is 2 × 10^11 Nm^−2 and coefficient of thermal expansion is 1.1 × 10^−5 K_1) Find the maximum length [...]
1.Using laws of exponents, simplify and write the answer in exponential form: (vi) 2^5 × 5^5
10
Oct
1.Using laws of exponents, simplify and write the answer in exponential form: (vi) 2^5 × 5^5 1.Using laws of exponents simplify and write the answer in exponential form: (vi) 2^5 × 5^5 October 10, 2020 Category: Chapter 13 - Exponents and Powers , Maths , NCERT Class 7 ,
1.Using laws of exponents, simplify and write the answer in exponential form: (v) (5^2)^3 ÷ 5^3
10
Oct
1.Using laws of exponents, simplify and write the answer in exponential form: (v) (5^2)^3 ÷ 5^3 1.Using laws of exponents simplify and write the answer in exponential form: (v) (5^2)^3 ÷ 5^3 October 10, 2020 Category: Chapter 13 - Exponents and Powers , Maths , NCERT Class 7 ,
1.Using laws of exponents, simplify and write the answer in exponential form: (iv) 7^x × 7^2
10
Oct
1.Using laws of exponents, simplify and write the answer in exponential form: (iv) 7^x × 7^2 1.Using laws of exponents simplify and write the answer in exponential form: (iv) 7^x × 7^2 October 10, 2020 Category: Chapter 13 - Exponents and Powers , Maths , NCERT Class 7 ,
Two wires are made of the same material and have the same volume. However wire 1 has cross-sectional area A and wire 2 has cross-sectional area 3A. If the length of wire 1 increases by Δx on applying force F, how much force is needed to stretch wire 2 by the same amount?
10
Oct
Two wires are made of the same material and have the same volume. However wire 1 has cross-sectional area A and wire 2 has cross-sectional area 3A. If the length of wire 1 increases by Δx on applying force F, how much force is needed to stretch wire 2 by the same amount? Find the [...]
1.Using laws of exponents, simplify and write the answer in exponential form: (iii) a^3 × a^2
10
Oct
1.Using laws of exponents, simplify and write the answer in exponential form: (iii) a^3 × a^2 1.Using laws of exponents simplify and write the answer in exponential form: (iii) a^3 × a^2 October 10, 2020 Category: Chapter 13 - Exponents and Powers , Maths , NCERT Class 7 ,
In Young’s double slit interference experiment, if the slit separation is made threefold, the fringe width becomes
10
Oct
In Young’s double slit interference experiment, if the slit separation is made threefold, the fringe width becomes if the slit separation is made threefold In Young's double slit interference experiment the fringe width becomes October 10, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
1.Using laws of exponents, simplify and write the answer in exponential form: (ii) 6^15 ÷ 6^10
10
Oct
1.Using laws of exponents, simplify and write the answer in exponential form: (ii) 6^15 ÷ 6^10 1.Using laws of exponents simplify and write the answer in exponential form: (ii) 6^15 ÷ 6^10 October 10, 2020 Category: Chapter 13 - Exponents and Powers , Maths , NCERT Class 7 ,