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The YDSE apparatus is as shown in figure. The condition for point P to be a dark fringe is
10
Oct
The YDSE apparatus is as shown in figure. The condition for point P to be a dark fringe is The YDSE apparatus is as shown in figure. The condition for point P to be a dark fringe is October 10, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
If the work done in blowing a bubble of volume V is W, then find the work done in blowing the bubble of volume 2 v from the same soap soilution.
10
Oct
If the work done in blowing a bubble of volume V is W, then find the work done in blowing the bubble of volume 2 v from the same soap soilution. If the work done in blowing a bubble of volume V is W then find the work done in blowing the bubble of volume [...]
A soap bubble of radius R is blown. After heating the solution a second bubble of radius 2 R is blown. The work required to blow the second bubble in comparison to that required for the first bubble is
10
Oct
A soap bubble of radius R is blown. After heating the solution a second bubble of radius 2 R is blown. The work required to blow the second bubble in comparison to that required for the first bubble is calculate the force required to take away the plate from the surface of water. if we [...]
2.Simplify and express each of the following in exponential form: (ix) 2^8 × a^5/4 ^3 × a^3
10
Oct
2.Simplify and express each of the following in exponential form: (ix) 2^8 × a^5/4 ^3 × a^3 2.Simplify and express each of the following in exponential form: (ix) 2^8 × a^5/4 ^3 × a^3 October 10, 2020 Category: Chapter 13 - Exponents and Powers , Maths , NCERT Class 7 ,
The path difference between two interfering waves at a point on the screen is lemda /6. The ratio of intensity at this point and that at the central bright fringe will be (assume that intensity
10
Oct
The path difference between two interfering waves at a point on the screen is lemda /6. The ratio of intensity at this point and that at the central bright fringe will be (assume that intensity The path difference between two interfering waves at a point on the screen is lemda /6. The ratio of intensity [...]
Two droplets merge with each other and forms a large droplets. In this process
10
Oct
Two droplets merge with each other and forms a large droplets. In this process Two droplets merge with each other and forms a large droplets. In this process October 10, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
2.Simplify and express each of the following in exponential form: (iv) 3 × 7^2 × 11^8/21 × 11^3
10
Oct
2.Simplify and express each of the following in exponential form: (iv) 3 × 7^2 × 11^8/21 × 11^3 2.Simplify and express each of the following in exponential form: (iv) 3 × 7^2 × 11^8/21 × 11^3 October 10, 2020 Category: Chapter 13 - Exponents and Powers , Maths , NCERT Class 7 ,
Two coherent light sources, each of wavelength lemda, are separated by a distance 3 lemda. The maximum number of minima formed on line AB which runs from – infinity to + infinity, is
10
Oct
Two coherent light sources, each of wavelength lemda, are separated by a distance 3 lemda. The maximum number of minima formed on line AB which runs from – infinity to + infinity, is are separated by a distance 3 lemda. The maximum number of minima formed on line AB which runs from - infinity to [...]
Calculate the work done in blowing up a soaqp bubble from an intial surface area of 0.50 cm^2 to a final surface area of 1.10 cm^2. The surface tension of soap solution is 30 dyne/ cm .
10
Oct
Calculate the work done in blowing up a soaqp bubble from an intial surface area of 0.50 cm^2 to a final surface area of 1.10 cm^2. The surface tension of soap solution is 30 dyne/ cm . Calculate the work done in blowing up a soaqp bubble from an intial surface area of 0.50 cm^2 [...]
In YDSE, D = 1 m, d = 1 mm, and lemda = 5000 nm. The distance of 100th maxima from the central maxima is
10
Oct
In YDSE, D = 1 m, d = 1 mm, and lemda = 5000 nm. The distance of 100th maxima from the central maxima is and lemda = 5000 nm. The distance of 100th maxima from the central maxima is D = 1 m d = 1 mm In YDSE October 10, 2020 Category: Uncategorised [...]