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4. Obtain the volume of rectangular boxes with the following length, breadth and height respectively. (ii) 2p, 4q, 8r
11
Oct
4. Obtain the volume of rectangular boxes with the following length, breadth and height respectively. (ii) 2p, 4q, 8r 4. Obtain the volume of rectangular boxes with the following length 4q 8r breadth and height respectively. (ii) 2p October 11, 2020 Category: Chapter 9 - Algebraic Expressions and Identities , Maths , NCERT Class 8 [...]
Figure shows a set up to perform Young’s double slit experiment. A monochromatic source of light is placed at S, S1 and S2 and act as coherent sources and interference pattern is
11
Oct
Figure shows a set up to perform Young’s double slit experiment. A monochromatic source of light is placed at S, S1 and S2 and act as coherent sources and interference pattern is Figure shows a set up to perform Young's double slit experiment. A monochromatic source of light is placed at S S1 and S2 [...]
4. Obtain the volume of rectangular boxes with the following length, breadth and height respectively. (i) 5a, 3a^2, 7a^4
11
Oct
4. Obtain the volume of rectangular boxes with the following length, breadth and height respectively. (i) 5a, 3a^2, 7a^4 3a^2 4. Obtain the volume of rectangular boxes with the following length 7a^4 breadth and height respectively. (i) 5a October 11, 2020 Category: Chapter 9 - Algebraic Expressions and Identities , Maths , NCERT Class 8 [...]
3. Complete the following table of products:
11
Oct
3. Complete the following table of products: 3. Complete the following table of products: October 11, 2020 Category: Chapter 9 - Algebraic Expressions and Identities , Maths , NCERT Class 8 ,
In the figures shown, Z1 and Z2 are two screens. Lines PO is the bisector line of S1S2 and S3S4. When Z1 is removed, resultant intensity at O due to slits S1 and S2 is I. Now, Z1 is
11
Oct
In the figures shown, Z1 and Z2 are two screens. Lines PO is the bisector line of S1S2 and S3S4. When Z1 is removed, resultant intensity at O due to slits S1 and S2 is I. Now, Z1 is In the figures shown resultant intensity at O due to slits S1 and S2 is I. [...]
2. Find the areas of rectangles with the following pairs of monomials as their lengths and breadths respectively. (p, q) ; (10m, 5n) ; (20x^2 , 5y^2) ; (4x, 3x^2) ; (3mn, 4np)
11
Oct
2. Find the areas of rectangles with the following pairs of monomials as their lengths and breadths respectively. (p, q) ; (10m, 5n) ; (20x^2 , 5y^2) ; (4x, 3x^2) ; (3mn, 4np) 2. Find the areas of rectangles with the following pairs of monomials as their lengths and breadths respectively. (p 3x^2) ; (3mn [...]
(c) Subtract 4p^2q – 3pq + 5pq^2 – 8p + 7q – 10 from 18 – 3p – 11q + 5pq – 2pq^2 + 5p^2q
11
Oct
(c) Subtract 4p^2q – 3pq + 5pq^2 – 8p + 7q – 10 from 18 – 3p – 11q + 5pq – 2pq^2 + 5p^2q (c) Subtract 4p^2q – 3pq + 5pq^2 – 8p + 7q – 10 from 18 – 3p – 11q + 5pq – 2pq^2 + 5p^2q October 11, 2020 Category: Chapter [...]
(b) Subtract 3xy + 5yz – 7zx from 5xy – 2yz – 2zx + 10xyz
11
Oct
(b) Subtract 3xy + 5yz – 7zx from 5xy – 2yz – 2zx + 10xyz (b) Subtract 3xy + 5yz – 7zx from 5xy – 2yz – 2zx + 10xyz October 11, 2020 Category: Chapter 9 - Algebraic Expressions and Identities , Maths , NCERT Class 8 ,
4. (a) Subtract 4a – 7ab + 3b + 12 from 12a – 9ab + 5b – 3
11
Oct
4. (a) Subtract 4a – 7ab + 3b + 12 from 12a – 9ab + 5b – 3 4. (a) Subtract 4a – 7ab + 3b + 12 from 12a – 9ab + 5b – 3 October 11, 2020 Category: Chapter 9 - Algebraic Expressions and Identities , Maths , NCERT Class 8 ,
3. Add the following. (iv) l^2 + m^2, m^2 + n^2, n^2 + l2, 2lm + 2mn + 2nl
11
Oct
3. Add the following. (iv) l^2 + m^2, m^2 + n^2, n^2 + l2, 2lm + 2mn + 2nl 2lm + 2mn + 2nl 3. Add the following. (iv) l^2 + m^2 m^2 + n^2 n^2 + l^2 October 11, 2020 Category: Chapter 9 - Algebraic Expressions and Identities , Maths , NCERT Class 8 [...]