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4. Simplify. (vi) (ab + bc)^2– 2ab²c
12
Oct
4. Simplify. (vi) (ab + bc)^2– 2ab²c 4. Simplify. (vi) (ab + bc)^2– 2ab²c October 12, 2020 Category: Chapter 9 - Algebraic Expressions and Identities , Maths , NCERT Class 8 ,
Work done in increasing the size of a soap bubble from a radius of 3 cm to 5 cm is nearly. ( surface tension of soap solution = 0.03 N/m)
12
Oct
Work done in increasing the size of a soap bubble from a radius of 3 cm to 5 cm is nearly. ( surface tension of soap solution = 0.03 N/m) Work done in increasing the size of a soap bubble from a radius of 3 cm to 5 cm is nearly. ( surface tension of [...]
4. Simplify. (v) (2.5p – 1.5q)^2 – (1.5p – 2.5q)^2
12
Oct
4. Simplify. (v) (2.5p – 1.5q)^2 – (1.5p – 2.5q)^2 4. Simplify. (v) (2.5p – 1.5q)^2 – (1.5p – 2.5q)^2 October 12, 2020 Category: Chapter 9 - Algebraic Expressions and Identities , Maths , NCERT Class 8 ,
4. Simplify. (iv) (4m + 5n)^2 + (5m + 4n)^2
12
Oct
4. Simplify. (iv) (4m + 5n)^2 + (5m + 4n)^2 4. Simplify. (iv) (4m + 5n)^2 + (5m + 4n)^2 October 12, 2020 Category: Chapter 9 - Algebraic Expressions and Identities , Maths , NCERT Class 8 ,
4. Simplify. (iii) (7m – 8n)^2 + (7m + 8n)^2
12
Oct
4. Simplify. (iii) (7m – 8n)^2 + (7m + 8n)^2 4. Simplify. (iii) (7m – 8n)^2 + (7m + 8n)^2 October 12, 2020 Category: Chapter 9 - Algebraic Expressions and Identities , Maths , NCERT Class 8 ,
The capillary tube is dipped in water vertically it is sufficiently long so that water rises to maximum height h in the tube te length of the portion immersed in water is l>h. The lower end of the tube is closed the tube is taken out and opened again then find length of the water column remaining in the tube.
12
Oct
The capillary tube is dipped in water vertically it is sufficiently long so that water rises to maximum height h in the tube te length of the portion immersed in water is l>h. The lower end of the tube is closed the tube is taken out and opened again then find length of the water [...]
3. Find the following squares by using the identities. (vi) (2xy + 5y)^2
12
Oct
3. Find the following squares by using the identities. (vi) (2xy + 5y)^2 3. Find the following squares by using the identities. (vi) (2xy + 5y)^2 October 12, 2020 Category: Chapter 9 - Algebraic Expressions and Identities , Maths , NCERT Class 8 ,
3. Find the following squares by using the identities. (v) (0.4p – 0.5q)^2
12
Oct
3. Find the following squares by using the identities. (v) (0.4p – 0.5q)^2 3. Find the following squares by using the identities. (v) (0.4p – 0.5q)^2 October 12, 2020 Category: Chapter 9 - Algebraic Expressions and Identities , Maths , NCERT Class 8 ,
There is an air bubble of radius 1.0 mm in a liquid of surface tension 0.075 N/m and density 1000 kg/m ^ 3 The bubble is at a depth of 10 cm below the free surface. By what amount is the pressure inside the bubble greater than the atmospheric pressure? (Take g = 9.8 m/s 2 )
12
Oct
There is an air bubble of radius 1.0 mm in a liquid of surface tension 0.075 N/m and density 1000 kg/m ^ 3 The bubble is at a depth of 10 cm below the free surface. By what amount is the pressure inside the bubble greater than the atmospheric pressure? (Take g = 9.8 m/s [...]
3. Find the following squares by using the identities. (iv) [(2m/3) + (3n/2)]^2
12
Oct
3. Find the following squares by using the identities. (iv) [(2m/3) + (3n/2)]^2 3. Find the following squares by using the identities. (iv) [(2m/3) + (3n/2)]^2 October 12, 2020 Category: Chapter 9 - Algebraic Expressions and Identities , Maths , NCERT Class 8 ,