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The drawing shows a parallel plate capacitor that is moving with a speed of 20 m/s through a 5.0-T magnetic field. The velocity is perpendicular to the magnetic field. The electric field within the capacitor has a value of 200 N/C, and each plate has an area of 5.0 x 10^-4 m^2. What is the magnetic force (magnitude and direction) exerted on the positive plate of the capacitor?
13
Oct
The drawing shows a parallel plate capacitor that is moving with a speed of 20 m/s through a 5.0-T magnetic field. The velocity is perpendicular to the magnetic field. The electric field within the capacitor has a value of 200 N/C, and each plate has an area of 5.0 x 10^-4 m^2. What is the [...]
Two charged particles move in the same direction with respect to the same magnetic field. particle 1 travels two times faster than particle 2. however, each particle experiences a magnetic force of the same magnitude. find the ratio q1 / q2 of the magnitudes of the charges.
13
Oct
Two charged particles move in the same direction with respect to the same magnetic field. particle 1 travels two times faster than particle 2. however, each particle experiences a magnetic force of the same magnitude. find the ratio q1 / q2 of the magnitudes of the charges. each particle experiences a magnetic force of the [...]
An electron moves through a uniform magnetic field given by B = Bxiˆ+(3Bx) jˆ. At a particular instant, the electron has the velocity v = ( 2.0iˆ+4.0jˆ) m/s and the magnetic force acting on its is ( 6.4×10^−19 N ) kˆ Find Bx.
13
Oct
An electron moves through a uniform magnetic field given by B = Bxiˆ+(3Bx) jˆ. At a particular instant, the electron has the velocity v = ( 2.0iˆ+4.0jˆ) m/s and the magnetic force acting on its is ( 6.4×10^−19 N ) kˆ Find Bx. An electron moves through a uniform magnetic field given by B = [...]
A particle of charge q > 0 is moving at speed v in the +z direction through a region of uniform magnetic field. The magnetic force on the particle F = F0 (3iˆ+4jˆ), where F0 is a positive constant. (a) Determine the components Bx, By and Bz or at least as many of the three components as is possible from the information given. (b) If it is given in addition that the magnetic field has magnitude 6 F0 qv , determine the magnitude of Bz.
13
Oct
A particle of charge q > 0 is moving at speed v in the +z direction through a region of uniform magnetic field. The magnetic force on the particle F = F0 (3iˆ+4jˆ), where F0 is a positive constant. (a) Determine the components Bx, By and Bz or at least as many of the three [...]
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A particle of charge q > 0 is moving at speed v in the +z direction through a region of uniform magnetic field. The magnetic force on the particle F = F0 (3iˆ+4jˆ) ,
By and Bz or at least as many of the three components as is possible from the information given. (b) If it is given in addition that the magnetic field has magnitude 6 F0 qv ,
determine the magnitude of Bz. ,
where F0 is a positive constant. (a) Determine the components Bx ,
A charged particle of mass 10 g and charge 50 muC, moves through a uniform magnetic field , in a region where the free- fall acceleration is -10 jm/s^2. Thje velocity of the particle is constant 20 i km/s, which is perpendiucular to the magnetic field. What , then, is the magnetic field?
13
Oct
A charged particle of mass 10 g and charge 50 muC, moves through a uniform magnetic field , in a region where the free- fall acceleration is -10 jm/s^2. Thje velocity of the particle is constant 20 i km/s, which is perpendiucular to the magnetic field. What , then, is the magnetic field? A charged [...]
A particle with charge 7.00 μC is moving with velocity v→=−( 4 × 10^3 m/s)jˆ. The magnetic force on the particle is measured to be F→=+(8.4 × 10^−2 N)iˆ−(5.60 × 10^−2 N)kˆ. a. Calculate all the components of the magnetic field you can from this information. b. Are there components of the magnetic field that cannot be determined by measurement of the force? Explain. c. Calculate the scalar product B→.F→. What is the angle between B→andF→?
13
Oct
A particle with charge 7.00 μC is moving with velocity v→=−( 4 × 10^3 m/s)jˆ. The magnetic force on the particle is measured to be F→=+(8.4 × 10^−2 N)iˆ−(5.60 × 10^−2 N)kˆ. a. Calculate all the components of the magnetic field you can from this information. b. Are there components of the magnetic field that [...]
When a proton has a velocity v→= (2iˆ+3jˆ) × 10^6 m/s, it experiences a force F→=−( 1.28 ×10^−13 kˆ) N. When its velocity is along the z-axis, it experiences a force along the x-axis. What is the magnetic field?
13
Oct
When a proton has a velocity v→= (2iˆ+3jˆ) × 10^6 m/s, it experiences a force F→=−( 1.28 ×10^−13 kˆ) N. When its velocity is along the z-axis, it experiences a force along the x-axis. What is the magnetic field? it experiences a force along the x-axis. What is the magnetic field? it experiences a force [...]
A particle with charge – 5.60 nC is moving in a uniform magnetic field → B = − ( 1.25 T ) ^ k . The magnetic force on the particle Is measured to be → F = − ( 3.36 × 10^ − 7 N ) ^ i + ( 7.42 × 10^ − 7 N ) ^ j . (a) Calculate the x-component of the velocity of the particle. (b) Calculate the y-component of the velocity of the particle. (c) Calculate the scalar product → v ⋅ → F .
13
Oct
A particle with charge – 5.60 nC is moving in a uniform magnetic field → B = − ( 1.25 T ) ^ k . The magnetic force on the particle Is measured to be → F = − ( 3.36 × 10^ − 7 N ) ^ i + ( 7.42 × 10^ − [...]
The force on a charged particle moving in a magnetic field can be computed as the vector sum of the force due to each separate component of the magnetic field. As an example, a particle with charge q is moving with speed v in the -y direction. It is moving in a uniform magnetic field B→=Bxiˆ+Byjˆ+Bzkˆ. a. What are the components of the force F→ exerted on the particle by the magnetic field? b. If q>0, what must the signs of the components of B→ be if the components of F→ are all non-negative? c. If q0, find the direction and magnitude of F in terms of |q|, v and Bx.
13
Oct
The force on a charged particle moving in a magnetic field can be computed as the vector sum of the force due to each separate component of the magnetic field. As an example, a particle with charge q is moving with speed v in the -y direction. It is moving in a uniform magnetic field [...]
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A charged particle has acceleration a vector = 2i^ + xj^ in a magnetic field B Vector= -3i^ +2 j^ -4k^. Find the value of x ,
The force on a charged particle moving in a magnetic field can be computed as the vector sum of the force due to each separate component of the magnetic field. As an example ,
A charged particle has acceleration a vector = 2i^ + xj^ in a magnetic field B Vector= -3i^ +2 j^ -4k^. Find the value of x
13
Oct
A charged particle has acceleration a vector = 2i^ + xj^ in a magnetic field B Vector= -3i^ +2 j^ -4k^. Find the value of x A charged particle has acceleration a vector = 2i^ + xj^ in a magnetic field B Vector= -3i^ +2 j^ -4k^. Find the value of x October 13, 2020 [...]