Question Answers
Sahay Sir > Question Answers
A charged particle moves with velocity v = ai + dj in a magnetic field B = Ai + Dj. The force acting on the particle has magnitude F. Then,
13
Oct
A charged particle moves with velocity v = ai + dj in a magnetic field B = Ai + Dj. The force acting on the particle has magnitude F. Then, A charged particle moves with velocity v = ai + dj in a magnetic field B = Ai + Dj. The force acting on the [...]
15. (a–4)(a–2) = a^2–8
13
Oct
15. (a–4)(a–2) = a^2–8 15. (a–4)(a–2) = a^2–8 October 13, 2020 Category: Chapter 14 - Factorisation , Maths , NCERT Class 8 ,
14. (a+4)(a+2) = a^2+8
13
Oct
14. (a+4)(a+2) = a^2+8 14. (a+4)(a+2) = a^2+8 October 13, 2020 Category: Chapter 14 - Factorisation , Maths , NCERT Class 8 ,
13. (2a+3b)(a–b) = 2a^2–3b^2
13
Oct
13. (2a+3b)(a–b) = 2a^2–3b^2 13. (2a+3b)(a–b) = 2a^2–3b^2 October 13, 2020 Category: Chapter 14 - Factorisation , Maths , NCERT Class 8 ,
12. (z+5)^2 = z^2+25
13
Oct
12. (z+5)^2 = z^2+25 12. (z+5)^2 = z^2+25 October 13, 2020 Category: Chapter 14 - Factorisation , Maths , NCERT Class 8 ,
11.(y–3)^2 = y^2–9
13
Oct
11.(y–3)^2 = y^2–9 11.(y–3)^2 = y^2–9 October 13, 2020 Category: Chapter 14 - Factorisation , Maths , NCERT Class 8 ,
10. Substituting x = – 3 in (c) x^2 + 5x gives (– 3)^2+5(–3) = – 9–15 = – 24
13
Oct
10. Substituting x = – 3 in (c) x^2 + 5x gives (– 3)^2+5(–3) = – 9–15 = – 24 10. Substituting x = – 3 in (c) x^2 + 5x gives (– 3)^2+5(–3) = – 9–15 = – 24 October 13, 2020 Category: Chapter 14 - Factorisation , Maths , NCERT Class 8 ,
A charged particle moves along a circle under the action of possible constant electric and ,magnetic fields, Which of the following are possible?
13
Oct
A charged particle moves along a circle under the action of possible constant electric and ,magnetic fields, Which of the following are possible? A charged particle moves along a circle under the action of possible constant electric and magnetic fields Which of the following are possible? October 13, 2020 Category: Uncategorised (JEE Advanced Physics by [...]
10. Substituting x = – 3 in (b) x^2 – 5x + 4 gives (– 3)^2– 5( – 3)+4 = 9–15+4 = – 2
13
Oct
10. Substituting x = – 3 in (b) x^2 – 5x + 4 gives (– 3)^2– 5( – 3)+4 = 9–15+4 = – 2 10. Substituting x = – 3 in (b) x^2 – 5x + 4 gives (– 3)^2– 5( – 3)+4 = 9–15+4 = – 2 October 13, 2020 Category: Chapter 14 - [...]
10. Substituting x = – 3 in (a) x^2 + 5x + 4 gives (– 3)^2+5(– 3)+4 = 9+2+4 = 15
13
Oct
10. Substituting x = – 3 in (a) x^2 + 5x + 4 gives (– 3)^2+5(– 3)+4 = 9+2+4 = 15 10. Substituting x = – 3 in (a) x^2 + 5x + 4 gives (– 3)^2+5(– 3)+4 = 9+2+4 = 15 October 13, 2020 Category: Chapter 14 - Factorisation , Maths , NCERT Class [...]