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A body executes SHM of period 3s under the influence of one force, and SHM of period 4s under the influence of a second force. When both the forces act simultaneously in the same direction, the period of oscillation will be
30
Oct
A body executes SHM of period 3s under the influence of one force, and SHM of period 4s under the influence of a second force. When both the forces act simultaneously in the same direction, the period of oscillation will be A body executes SHM of period 3s under the influence of one force and [...]
The following figure shows the displacement versus time graph for two particles A and B executing simple harmonic motions. The ratio of their maximum velocities is
30
Oct
The following figure shows the displacement versus time graph for two particles A and B executing simple harmonic motions. The ratio of their maximum velocities is The following figure shows the displacement versus time graph for two particles A and B executing simple harmonic motions. The ratio of their maximum velocities is October 30, 2020 [...]
The minimum phase difference between the two simple harmonic oscillations y1=1/2sinωt+(3–√/2)cosωt and y2=sinωt+cosωt is
30
Oct
The minimum phase difference between the two simple harmonic oscillations y1=1/2sinωt+(3–√/2)cosωt and y2=sinωt+cosωt is The minimum phase difference between the two simple harmonic oscillations y1=1/2sinωt+(3–√/2)cosωt and y2=sinωt+cosωt is October 30, 2020 Category: Cengage NEET by C.P Singh , Chapter 13 - Simple Harmonic Motion , Part 1 ,
A body is initially at rest. It undergoes one-dimensional motion with constant acceleration. The power delivered to it at time t is proportional to
30
Oct
A body is initially at rest. It undergoes one-dimensional motion with constant acceleration. The power delivered to it at time t is proportional to A body is initially at rest. It undergoes one-dimensional motion with constant acceleration. The power delivered to it at time t is proportional to October 30, 2020 Category: Chapter 5 - [...]
The potential energy function for a particle executing linear simple harmonic motion is given by V(x) = kx 2 /2, where k is the force constant of the oscillator. For k = 0.5 Nm^−1 , the graph of V(x) versus x is shown in Fig. Show that a particle of total energy 1 J moving under this potential must turn back when it reaches x = ± 2 m.
30
Oct
The potential energy function for a particle executing linear simple harmonic motion is given by V(x) = kx 2 /2, where k is the force constant of the oscillator. For k = 0.5 Nm^−1 , the graph of V(x) versus x is shown in Fig. Show that a particle of total energy 1 J moving [...]
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the graph of V(x) versus x is shown in Fig. Show that a particle of total energy 1 J moving under this potential must turn back when it reaches x = ± 2 m. ,
The potential energy function for a particle executing linear simple harmonic motion is given by V(x) = kx 2 /2 ,
where k is the force constant of the oscillator. For k = 0.5 Nm^−1 ,
Given below are examples of some potential energy functions in one dimension. Mark the total energy of the particle is indicated by a cross on the energy axis. In each case, specify the regions, if any, in which the particle cannot be found for the given energy. Also, indicate the minimum total energy the particle must have in each case. Think of simple physical contexts for which these potential energy shapes are relevant.
30
Oct
Given below are examples of some potential energy functions in one dimension. Mark the total energy of the particle is indicated by a cross on the energy axis. In each case, specify the regions, if any, in which the particle cannot be found for the given energy. Also, indicate the minimum total energy the particle [...]
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Given below are examples of some potential energy functions in one dimension. Mark the total energy of the particle is indicated by a cross on the energy axis. In each case ,
if any ,
in which the particle cannot be found for the given energy. Also ,
indicate the minimum total energy the particle must have in each case. Think of simple physical contexts for which these potential energy shapes are relevant. ,
specify the regions ,
The ratio of the amplitude of the simple pendulum oscillation gives by y1 = A sin ωt and y2 = 2/A sin ωt + 2/A cos ωt is
30
Oct
The ratio of the amplitude of the simple pendulum oscillation gives by y1 = A sin ωt and y2 = 2/A sin ωt + 2/A cos ωt is The ratio of the amplitude of the simple pendulum oscillation gives by y1 = A sin ωt and y2 = 2/A sin ωt + 2/A [...]
The diagram below shows a sinusoidal curve. The equation of the curve will be
30
Oct
The diagram below shows a sinusoidal curve. The equation of the curve will be The diagram below shows a sinusoidal curve. The equation of the curve will be October 30, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
A particle is performing SHM with amplitude a and time period T. Its acceleration f varies with time as shown in the following figure. If at time t, kinetic energy of the particle is
30
Oct
A particle is performing SHM with amplitude a and time period T. Its acceleration f varies with time as shown in the following figure. If at time t, kinetic energy of the particle is A particle is performing SHM with amplitude a and time period T. Its acceleration f varies with time as shown in [...]
A body is performing simple harmonic motion with amplitude a and time period T. Variation of its acceleration (f) with time (t) is shown in the given figure. If at time t, velocity of the body is v,
30
Oct
A body is performing simple harmonic motion with amplitude a and time period T. Variation of its acceleration (f) with time (t) is shown in the given figure. If at time t, velocity of the body is v, A body is performing simple harmonic motion with amplitude a and time period T. Variation of its [...]