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The equilibrium constant for the reaction CO(g)+H2O(g)⇔CO2(g)+H2(g) is 5. How many moles of CO2 must be added to 1 litre container already containing 3 moles each of CO and H2O to make 2M equilibrium concentration of CO?
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Nov
The equilibrium constant for the reaction CO(g)+H2O(g)⇔CO2(g)+H2(g) is 5. How many moles of CO2 must be added to 1 litre container already containing 3 moles each of CO and H2O to make 2M equilibrium concentration of CO? CO(g) + Cl2(g) ⇌ COCl2(g) For the reaction the value of Kp /Kc is equal to: November 11, [...]
In a single slit diffraction experiment the width of the slit is reduced by half. Which of the following needs to be done if the width of the central maxima has to remain the same ?
11
Nov
In a single slit diffraction experiment the width of the slit is reduced by half. Which of the following needs to be done if the width of the central maxima has to remain the same ? In a single slit diffraction experiment the width of the slit is reduced by half. Which of the following [...]
At 273 K and 1 atm, 10 litre of N2O4 decomposes to NO2 according to equation : N2O4 ⇌ 2NO2(g) What is degree of dissociation (a) when the original volume is 25% less that of existing volume?
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Nov
At 273 K and 1 atm, 10 litre of N2O4 decomposes to NO2 according to equation : N2O4 ⇌ 2NO2(g) What is degree of dissociation (a) when the original volume is 25% less that of existing volume? 10 litre of N2O4 decomposes to NO2 according to equation : N2O4 ⇌ 2NO2(g) What is degree of [...]
The equilibrium constant KP for the reaction H2(g) +CO2(g) =H2O(g) +CO(g) is 4 at 1660°C. Initially 0.80 mole H2 and 0.80 mole CO2 are injected into a 5L flask. What is the equilibrium concentration of CO2?
11
Nov
The equilibrium constant KP for the reaction H2(g) +CO2(g) =H2O(g) +CO(g) is 4 at 1660°C. Initially 0.80 mole H2 and 0.80 mole CO2 are injected into a 5L flask. What is the equilibrium concentration of CO2? CO(g) + Cl2(g) ⇌ COCl2(g) For the reaction the value of Kp /Kc is equal to: November 11, 2020 [...]
A catalyst increases the rate of reaction by:
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Nov
A catalyst increases the rate of reaction by: A catalyst increases the rate of reaction by: November 11, 2020 Category: Chapter 5 - Chemical Equilibrium (Level 1 and Level 2) , N Awasthi Physical Chemistry ,
At a certain temperature, only 50% HI is dissociated at equilibrium in the following reaction: 2HI(g)⇔H2(g)+I2(g) the equilibrium constant for this reaction is:
11
Nov
At a certain temperature, only 50% HI is dissociated at equilibrium in the following reaction: 2HI(g)⇔H2(g)+I2(g) the equilibrium constant for this reaction is: At a certain temperature only 50% HI is dissociated at equilibrium in the following reaction: 2HI(g)⇔H2(g)+I2(g) the equilibrium constant for this reaction is: November 11, 2020 Category: Chapter 5 - Chemical Equilibrium [...]
On increasing temperature, the rate of a reaction: (a) always increases (b) always decreases
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Nov
On increasing temperature, the rate of a reaction: (a) always increases (b) always decreases On increasing temperature the rate of a reaction: (a) always increases (b) always decreases November 11, 2020 Category: Chapter 5 - Chemical Equilibrium (Level 1 and Level 2) , N Awasthi Physical Chemistry ,
The Fraunhofer diffraction pattern of a single slit is formed at the focal plane of a lens of focal length 1m. The width of the slit is 0.3 mm. If the third minimum is formed at a distance of 5 mm from the central maximum then calculate the wavelength of light.
11
Nov
The Fraunhofer diffraction pattern of a single slit is formed at the focal plane of a lens of focal length 1m. The width of the slit is 0.3 mm. If the third minimum is formed at a distance of 5 mm from the central maximum then calculate the wavelength of light. is The angular width [...]
The value of n (i.e. principal quantum number) for the valence shell of palladium is (atomic number = 40)
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Nov
The value of n (i.e. principal quantum number) for the valence shell of palladium is (atomic number = 40) The value of n (i.e. principal quantum number) for the valence shell of palladium is (atomic number = 40) November 11, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
The first ionisation potential of Na is 5.1 eV. The value of electron gain enthalpy of Na + will be
11
Nov
The first ionisation potential of Na is 5.1 eV. The value of electron gain enthalpy of Na + will be The first ionisation potential of Na is 5.1 eV. The value of electron gain enthalpy of Na + will be November 11, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,