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A number of resistors are conncected as shown in the figure. The equivalent resistance between A and B is
11
Nov
A number of resistors are conncected as shown in the figure. The equivalent resistance between A and B is A number of resistors are conncected as shown in the figure. The equivalent resistance between A and B is November 11, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
Purpose of smelting of an ore is (a) To oxidise it (b) To reduce it (c) To remove vapourisable impurities (d) To obtain an alloy
11
Nov
Purpose of smelting of an ore is (a) To oxidise it (b) To reduce it (c) To remove vapourisable impurities (d) To obtain an alloy Purpose of smelting of an ore is (a) To oxidise it (b) To reduce it (c) To remove vapourisable impurities (d) To obtain an alloy November 11, 2020 Category: Uncategorised [...]
A substance which reacts with gangue to form fusible material is called (a) Flux (b) Catalyst (c) Ore (d) Slag
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Nov
A substance which reacts with gangue to form fusible material is called (a) Flux (b) Catalyst (c) Ore (d) Slag A substance which reacts with gangue to form fusible material is called (a) Flux (b) Catalyst (c) Ore (d) Slag November 11, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
When lime stone is heated strongly, it gives off CO2. In metallurgy this process is known as (a) Calcination (b) Roasting (c) Smelting (d) Ore dressing
11
Nov
When lime stone is heated strongly, it gives off CO2. In metallurgy this process is known as (a) Calcination (b) Roasting (c) Smelting (d) Ore dressing it gives off CO2. In metallurgy this process is known as (a) Calcination (b) Roasting (c) Smelting (d) Ore dressing When lime stone is heated strongly November 11, 2020 [...]
Roasting is generally done in case of the following (a) Oxides ores (b) Silicate ores (c) Sulphide ores (d) Carbonate ores
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Nov
Roasting is generally done in case of the following (a) Oxides ores (b) Silicate ores (c) Sulphide ores (d) Carbonate ores Roasting is generally done in case of the following (a) Oxides ores (b) Silicate ores (c) Sulphide ores (d) Carbonate ores November 11, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP [...]
Assume that the decomposition of HNO3 can be represented by the following equation 4HNO3(g)⇔4NO2(g)+2H2O(g)+O2(g) and the reaction approaches equilibrium at 400K temperature and 30 atm pressure. At equilibrium partial pressure of HNO3 is 2 atm Calculate Kc in (mol/L−K) at 400K (Use:R=0.08atm−L/mol−K)
11
Nov
Assume that the decomposition of HNO3 can be represented by the following equation 4HNO3(g)⇔4NO2(g)+2H2O(g)+O2(g) and the reaction approaches equilibrium at 400K temperature and 30 atm pressure. At equilibrium partial pressure of HNO3 is 2 atm Calculate Kc in (mol/L−K) at 400K (Use:R=0.08atm−L/mol−K) The most stable oxides of nitrogen will be : November 11, 2020 Category: [...]
The gas A2 in the left flask allowed to react with gas B2 present in right flask as A2(g)+B2(g)⇔2AB(g),Kc=4 at 27^∘C. What is the concentration of AB when equilibrium is established ?
11
Nov
The gas A2 in the left flask allowed to react with gas B2 present in right flask as A2(g)+B2(g)⇔2AB(g),Kc=4 at 27^∘C. What is the concentration of AB when equilibrium is established ? Kc=4 at 27^∘C. What is the concentration of AB when equilibrium is established ? The gas A2 in the left flask allowed to [...]
One mole of N2 (g) is mixed with 2 moles of H 2(g) in a 4 litre vessel. If 50% of N2(g) is converted to H2(g) by the following reaction : N2 (g)+3H2(g)⇌2NH3 (g) What will be the value of Kc for the following equilibrium? NH3 (g)⇌ 2/1 N2 (g) + 2/3 H2 (g)
11
Nov
One mole of N2 (g) is mixed with 2 moles of H 2(g) in a 4 litre vessel. If 50% of N2(g) is converted to H2(g) by the following reaction : N2 (g)+3H2(g)⇌2NH3 (g) What will be the value of Kc for the following equilibrium? NH3 (g)⇌ 2/1 N2 (g) + 2/3 H2 (g) [...]
The following equilibrium constants were determined at 1120K: 2CO(g)⇔C(s)+CO2(g),,Kp1=10−114atm−1 CO(g)+Cl2(g)⇔COCl2(g),,Kp2=6×10−3atm−1 What is the equilibrium constant Kc for the following reaction at 1120K: C(s)+CO2(g)+2Cl2(g)⇔2COCl2(g)
11
Nov
The following equilibrium constants were determined at 1120K: 2CO(g)⇔C(s)+CO2(g),,Kp1=10−114atm−1 CO(g)+Cl2(g)⇔COCl2(g),,Kp2=6×10−3atm−1 What is the equilibrium constant Kc for the following reaction at 1120K: C(s)+CO2(g)+2Cl2(g)⇔2COCl2(g) Kp1=10−114atm−1 CO(g)+Cl2(g)⇔COCl2(g) Kp2=6×10−3atm−1 What is the equilibrium constant Kc for the following reaction at 1120K: C(s)+CO2(g)+2Cl2(g)⇔2COCl2(g) The following equilibrium constants were determined at 1120K: 2CO(g)⇔C(s)+CO2(g) November 11, 2020 Category: Chapter 5 - [...]
The standard free energy change of a reaction is ΔG∘=−115 kJ mol^-1 at 298 K. Calculate the the value of log10 Kp (R=8.314 jK^−1mol^−1)
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Nov
The standard free energy change of a reaction is ΔG∘=−115 kJ mol^-1 at 298 K. Calculate the the value of log10 Kp (R=8.314 jK^−1mol^−1) The standard free energy change of a reaction is ΔG∘=−115 kJ mol^-1 at 298 K. Calculate the the value of log10 Kp (R=8.314 jK^−1mol^−1) November 11, 2020 Category: Chapter 5 - [...]