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A wave is represented by the equation y=0.1sin(100πt−kx) If wave velocity is 100ms^−1 , its wave length is equal to
11
Nov
A wave is represented by the equation y=0.1sin(100πt−kx) If wave velocity is 100ms^−1 , its wave length is equal to A wave is represented by the equation y=0.1sin(100πt−kx) If wave velocity is 100ms^−1 its wave length is equal to November 11, 2020 Category: Chapter 17 - Wave Motion , MTG NEET Physics , Part 1 [...]
A wave of frequency 500 hz has velocity 360 m/s. The phase difference between the two point is 60 degree, then the path difference is
11
Nov
A wave of frequency 500 hz has velocity 360 m/s. The phase difference between the two point is 60 degree, then the path difference is A wave of frequency 500 hz has velocity 360 m/s. The phase difference between the two point is 60 degree then the path difference is November 11, 2020 Category: Chapter [...]
Two waves having equation x1=3sinωτ and x2=4sin(ωτ+90^∘) are superimposed. The amplitude of the resultant wave is
11
Nov
Two waves having equation x1=3sinωτ and x2=4sin(ωτ+90^∘) are superimposed. The amplitude of the resultant wave is Two waves having equation x1=3sinωτ and x2=4sin(ωτ+90^∘) are superimposed. The amplitude of the resultant wave is November 11, 2020 Category: Chapter 17 - Wave Motion , MTG NEET Physics , Part 1 ,
Two waves are represented by the equations y1=asin(ω+kx+0.57)m and y2=acos(ωt+kx)m where x is in meter and t in sec. The phase difference between them is
11
Nov
Two waves are represented by the equations y1=asin(ω+kx+0.57)m and y2=acos(ωt+kx)m where x is in meter and t in sec. The phase difference between them is Two waves are represented by the equations y1=asin(ω+kx+0.57)m and y2=acos(ωt+kx)m where x is in meter and t in sec. The phase difference between them is November 11, 2020 Category: Chapter [...]
y=4sin(15πx)cos(96πt),where x and y are in cm and t in seconds. the velocity of the particles atx =7.5cm and t=0.25s is
11
Nov
y=4sin(15πx)cos(96πt),where x and y are in cm and t in seconds. the velocity of the particles atx =7.5cm and t=0.25s is where x and y are in cm and t in seconds. the velocity of the particles atx =7.5cm and t=0.25s is y=4sin(15πx)cos(96πt) November 11, 2020 Category: Chapter 17 - Wave Motion , MTG NEET [...]
If the speed of the wave shown in the figure is 330 m/s in the given medium, then the equation of the wave propagation in the positive x-direction will be ……………. (a) y = 0.05 sin 2π (4000t – 12.5x) m (b) y = 0.05 sin 2π (4000t – 122.5x) m (c) y = 0.05 sin 2π (3300t – 10x) m (d) y = 0.05 sin 2π (3300t – 10x) m
11
Nov
If the speed of the wave shown in the figure is 330 m/s in the given medium, then the equation of the wave propagation in the positive x-direction will be ……………. (a) y = 0.05 sin 2π (4000t – 12.5x) m (b) y = 0.05 sin 2π (4000t – 122.5x) m (c) y = 0.05 [...]
When N2O5 is heated at certain temperature, it dissociates as N2O5 (g)⇌N2O3 (g)+O 2 (g);Kc =2.5. At the same time N2O3 also decomposes as: N2 O3 (g)⇌N 2O+O 2(g). If initially 4.0 moles of N2O 5 are taken in 1.0 litre flask and allowed to dissociation, concentration of O2 at equilibrium is 2.5M. Equilibrium concentration of N2O5 is:
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Nov
When N2O5 is heated at certain temperature, it dissociates as N2O5 (g)⇌N2O3 (g)+O 2 (g);Kc =2.5. At the same time N2O3 also decomposes as: N2 O3 (g)⇌N 2O+O 2(g). If initially 4.0 moles of N2O 5 are taken in 1.0 litre flask and allowed to dissociation, concentration of O2 at equilibrium is 2.5M. Equilibrium [...]
Calculate ΔrG for the reaction at 27^oC. H2 (g)+2Ag +(aq)⇌2Ag(s)+2H +(aq) Given: PH2 =0.5 bar; [Ag + ]=10 −5 M; [H+ ] = 10^−3 M;Δ r G^o[Ag + (aq)]=77.1kJ/mol
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Nov
Calculate ΔrG for the reaction at 27^oC. H2 (g)+2Ag +(aq)⇌2Ag(s)+2H +(aq) Given: PH2 =0.5 bar; [Ag + ]=10 −5 M; [H+ ] = 10^−3 M;Δ r G^o[Ag + (aq)]=77.1kJ/mol Calculate ΔrG for the reaction at 27^oC. H2 (g)+2Ag +(aq)⇌2Ag(s)+2H +(aq) Given: PH2 =0.5 bar; [Ag + ]=10 −5 M; [H+ ] = 10^−3 M;Δ r [...]
The equilibrium constant for the ionization of RNH2 (g) in water as RNH2(g)+H2O(l)⇔RNH+3(aq)+OH−(aq) is 8×10^−6 at 25^∘C. find the pH of a solution at equilibrium when pressure of RNH2(g) is 0.5 bar :
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Nov
The equilibrium constant for the ionization of RNH2 (g) in water as RNH2(g)+H2O(l)⇔RNH+3(aq)+OH−(aq) is 8×10^−6 at 25^∘C. find the pH of a solution at equilibrium when pressure of RNH2(g) is 0.5 bar : The equilibrium constant for the ionization of RNH2 (g) in water as RNH2(g)+H2O(l)⇔RNH+3(aq)+OH−(aq) is 8×10^−6 at 25^∘C. find the pH of a [...]
At 800 degree C, the following equilibrium is established as: F2(g)⇌2F(g) The composition of equilibrium may be determined by measuring the rate of effusion of the mixture through a pinhole. It is found that at 800^oC and 1 atm mixture effuses 1.6 times as fast as SO2 effuses under the similar conditions. (At.wt. of F=19). What is the value of Kp (in atm)?
11
Nov
At 800 degree C, the following equilibrium is established as: F2(g)⇌2F(g) The composition of equilibrium may be determined by measuring the rate of effusion of the mixture through a pinhole. It is found that at 800^oC and 1 atm mixture effuses 1.6 times as fast as SO2 effuses under the similar conditions. (At.wt. of F=19). [...]