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To obtain chromium from chromic oxide (Cr2O3), the method used is (a) Alumino-thermic process (b) Electrolytic reduction (c) Carbon reduction
12
Nov
To obtain chromium from chromic oxide (Cr2O3), the method used is (a) Alumino-thermic process (b) Electrolytic reduction (c) Carbon reduction the method used is (a) Alumino-thermic process (b) Electrolytic reduction (c) Carbon reduction To obtain chromium from chromic oxide (Cr2O3) November 12, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
Iron is obtained on a large scale from Fe2O3 by (a) Reduction with Al (b) Reduction with CO (c) Reduction with H2
12
Nov
Iron is obtained on a large scale from Fe2O3 by (a) Reduction with Al (b) Reduction with CO (c) Reduction with H2 Iron is obtained on a large scale from Fe2O3 by (a) Reduction with Al (b) Reduction with CO (c) Reduction with H2 November 12, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma [...]
A car moving with velocity 50 m s towards a wall sounds a horn of frequency of 1.2 kHz. The velocity of sound is 350 m/s, the apparent frequency of the echo heard by the driver is
12
Nov
A car moving with velocity 50 m s towards a wall sounds a horn of frequency of 1.2 kHz. The velocity of sound is 350 m/s, the apparent frequency of the echo heard by the driver is A car moving with velocity 50 m s towards a wall sounds a horn of frequency of 1.2 [...]
In aluminium extraction by the Baeyer’s process, alumina is extracted from bauxite by sodium hydroxide at high temperatures and pressures
12
Nov
In aluminium extraction by the Baeyer’s process, alumina is extracted from bauxite by sodium hydroxide at high temperatures and pressures alumina is extracted from bauxite by sodium hydroxide at high temperatures and pressures In aluminium extraction by the Baeyer's process November 12, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
The frequencies of two tuning forks A and B are respectively 1.5% more 2.5% less than that of tuning fork C. When A and B sounded together, 12 beats are produced in 1 second. The frequency of tuning fork C is
12
Nov
The frequencies of two tuning forks A and B are respectively 1.5% more 2.5% less than that of tuning fork C. When A and B sounded together, 12 beats are produced in 1 second. The frequency of tuning fork C is 12 beats are produced in 1 second. The frequency of tuning fork C is [...]
Two uniform wires are vibrating simultaneously in their fundamental modes. The tensions, lengths, diameters and the densities of the two wires are in the ratio 8:1, 36:35, 4:1 and 1:2 respectively. If the note of the higher pitch has a frequency 360 hertz, the number of beats produced per second is:
12
Nov
Two uniform wires are vibrating simultaneously in their fundamental modes. The tensions, lengths, diameters and the densities of the two wires are in the ratio 8:1, 36:35, 4:1 and 1:2 respectively. If the note of the higher pitch has a frequency 360 hertz, the number of beats produced per second is: 36:35 4:1 and 1:2 [...]
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36:35 ,
4:1 and 1:2 respectively. If the note of the higher pitch has a frequency 360 hertz ,
diameters and the densities of the two wires are in the ratio 8:1 ,
lengths ,
the number of beats produced per second is: ,
Two uniform wires are vibrating simultaneously in their fundamental modes. The tensions ,
When two sound sources of the same amplitude but of slightly different frequencies v1 and v2 are sounded simultaneously, the sound one hears has a frequency equal to
12
Nov
When two sound sources of the same amplitude but of slightly different frequencies v1 and v2 are sounded simultaneously, the sound one hears has a frequency equal to the sound one hears has a frequency equal to When two sound sources of the same amplitude but of slightly different frequencies v1 and v2 are sounded [...]
The potential difference Va- Vb for the circuit shown in figure is -(22/x) V. Find the value of x.
12
Nov
The potential difference Va- Vb for the circuit shown in figure is -(22/x) V. Find the value of x. The potential difference Va- Vb for the circuit shown in figure is -(22/x) V. Find the value of x. November 12, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
When two tuning forks (fork 1 and fork 2) are sounded simultaneously, 4 beats per second are heard. Now some tape is attached on the prong of the fork 2. When the tuning fork are sounded again, 6 beats per second are heard. If the frequency of fork 1 is 200Hz, then what was the original frequency of fork 2 ?
12
Nov
When two tuning forks (fork 1 and fork 2) are sounded simultaneously, 4 beats per second are heard. Now some tape is attached on the prong of the fork 2. When the tuning fork are sounded again, 6 beats per second are heard. If the frequency of fork 1 is 200Hz, then what was the [...]
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4 beats per second are heard. Now some tape is attached on the prong of the fork 2. When the tuning fork are sounded again ,
6 beats per second are heard. If the frequency of fork 1 is 200Hz ,
then what was the original frequency of fork 2? ,
When two tuning forks (fork 1 and fork 2) are sounded simultaneously ,
The area of cross section, length, and density of a piece of metal of atomic weight 60 are 10^−6 m ^2 , 1 m, and 5 × 10 ^ 3 kgm −3 , respectively. If every atom contributes one free electron, find the drift velocity (in mms −1 ) of electrons in the metal when a current of 16 A passes through it. Avogadro’s number is N A= 6 × 10 ^23 /mol and charge on an electron is e = 1.6 × 10 ^−19 C
12
Nov
The area of cross section, length, and density of a piece of metal of atomic weight 60 are 10^−6 m ^2 , 1 m, and 5 × 10 ^ 3 kgm −3 , respectively. If every atom contributes one free electron, find the drift velocity (in mms −1 ) of electrons in the metal when [...]
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1 m ,
and 5 × 10 ^ 3 kgm −3 ,
and density of a piece of metal of atomic weight 60 are 10^−6 m ^2 ,
find the drift velocity (in mms −1 ) of electrons in the metal when a current of 16 A passes through it. Avogadro's number is N A= 6 × 10 ^23 /mol and charge on an electron is e = 1.6 × 10 ^−19 C ,
length ,
respectively. If every atom contributes one free electron ,
The area of cross section ,