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Consider the following reversible chemical reactions : A2(g) + B2(g) ⇌ K12AB(g) ….(1) 6AB(g) ⇌ K23A2(g) + 3B2(g) …(2) The relation between K1 and K2 is :
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Nov
Consider the following reversible chemical reactions : A2(g) + B2(g) ⇌ K12AB(g) ….(1) 6AB(g) ⇌ K23A2(g) + 3B2(g) …(2) The relation between K1 and K2 is : Consider the following reversible chemical reactions : A2(g) + B2(g) ⇌ K12AB(g) ....(1) 6AB(g) ⇌ K23A2(g) + 3B2(g) ...(2) The relation between K1 and K2 is : November [...]
Posted in: Chapter 7 - Equilibrium , Chemistry , JEE Adv and Mains Chemistry 41 Years Solved Video Solutions 1979 - 2019 ,
Tags: Consider the following reversible chemical reactions : A2(g) + B2(g) ⇌ K12AB(g) ....(1) 6AB(g) ⇌ K23A2(g) + 3B2(g) ...(2) The relation between K1 and K2 is : ,
The value of Kp/KC for the following reactions at 300K are, respectively : (At 300K, RT = 24.62 dm^3 atm mol^−1) N2(g)+O2(g)↽−−⇀2NO(g) N2O4(g)↽−−⇀2NO2(g) N2(g)+3H2(g)↽−−⇀2NH3(g)
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Nov
The value of Kp/KC for the following reactions at 300K are, respectively : (At 300K, RT = 24.62 dm^3 atm mol^−1) N2(g)+O2(g)↽−−⇀2NO(g) N2O4(g)↽−−⇀2NO2(g) N2(g)+3H2(g)↽−−⇀2NH3(g) respectively : (At 300K RT = 24.62 dm^3 atm mol^−1) N2(g)+O2(g)↽−−⇀2NO(g) N2O4(g)↽−−⇀2NO2(g) N2(g)+3H2(g)↽−−⇀2NH3(g) The value of Kp/KC for the following reactions at 300K are November 16, 2020 Category: Chapter 7 - [...]
Posted in: Chapter 7 - Equilibrium , Chemistry , JEE Adv and Mains Chemistry 41 Years Solved Video Solutions 1979 - 2019 ,
Tags: respectively : (At 300K , RT = 24.62 dm^3 atm mol^−1) N2(g)+O2(g)↽−−⇀2NO(g) N2O4(g)↽−−⇀2NO2(g) N2(g)+3H2(g)↽−−⇀2NH3(g) , The value of Kp/KC for the following reactions at 300K are ,
5⋅1g NH4SH is introduced in 3.0 L evacuated flask at 327^∘C. 30% of the solid NH4SH decomposed to NH3 and H2S as gases. The Kp of the reaction at 327^∘C is (R=0⋅082 atm mol^−1K^−1, Molar mass of S = 32 g mol^-1, molar mass of N = 14 g mol^−1)
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Nov
5⋅1g NH4SH is introduced in 3.0 L evacuated flask at 327^∘C. 30% of the solid NH4SH decomposed to NH3 and H2S as gases. The Kp of the reaction at 327^∘C is (R=0⋅082 atm mol^−1K^−1, Molar mass of S = 32 g mol^-1, molar mass of N = 14 g mol^−1) 5⋅1g NH4SH is introduced in [...]
Posted in: Chapter 7 - Equilibrium , Chemistry , JEE Adv and Mains Chemistry 41 Years Solved Video Solutions 1979 - 2019 ,
Tags: 5⋅1g NH4SH is introduced in 3.0 L evacuated flask at 327^∘C. 30% of the solid NH4SH decomposed to NH3 and H2S as gases. The Kp of the reaction at 327^∘C is (R=0⋅082 atm mol^−1K^−1 , molar mass of N = 14 g mol^−1) , Molar mass of S = 32 g mol^-1 ,
Consider the reaction, N2(g)+3H2(g)↽−−⇀2NH3(g) The equilibrium constant of the above reaction is KP. If pure ammonia is left to dissociate, the partial pressure of ammonia at equilibrium is given by (Assume that PNH3 < < P total at equilibrium)
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Nov
Consider the reaction, N2(g)+3H2(g)↽−−⇀2NH3(g) The equilibrium constant of the above reaction is KP. If pure ammonia is left to dissociate, the partial pressure of ammonia at equilibrium is given by (Assume that PNH3 < < P total at equilibrium) Consider the reaction N2(g)+3H2(g)↽−−⇀2NH3(g) The equilibrium constant of the above reaction is KP. If pure ammonia [...]
Posted in: Chapter 7 - Equilibrium , Chemistry , JEE Adv and Mains Chemistry 41 Years Solved Video Solutions 1979 - 2019 ,
Tags: Consider the reaction , N2(g)+3H2(g)↽−−⇀2NH3(g) The equilibrium constant of the above reaction is KP. If pure ammonia is left to dissociate , the partial pressure of ammonia at equilibrium is given by (Assume that PNH3 < < P total at equilibrium) ,
Two solids dissociate as follows A(s)↽−−⇀B(g) + C(g);Kp1 = x atm^2 D(s)↽−−⇀C(g) + E(g);Kp2 = y atm^2 The total pressure when both the solids dissociate simultaneously is :-
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Nov
Two solids dissociate as follows A(s)↽−−⇀B(g) + C(g);Kp1 = x atm^2 D(s)↽−−⇀C(g) + E(g);Kp2 = y atm^2 The total pressure when both the solids dissociate simultaneously is :- Two solids dissociate as follows A(s)↽−−⇀B(g) + C(g);Kp1 = x atm^2 D(s)↽−−⇀C(g) + E(g);Kp2 = y atm^2 The total pressure when both the solids dissociate simultaneously is [...]
Posted in: Chapter 7 - Equilibrium , Chemistry , JEE Adv and Mains Chemistry 41 Years Solved Video Solutions 1979 - 2019 ,
Tags: Two solids dissociate as follows A(s)↽−−⇀B(g) + C(g);Kp1 = x atm^2 D(s)↽−−⇀C(g) + E(g);Kp2 = y atm^2 The total pressure when both the solids dissociate simultaneously is :- ,
In a chemical reaction, A + 2B (K) ⇋ 2C + D, the initial concentration of B was 1.5 times of the concentration of A, but the equilibrium concentrations of A and B were found to be equal. The equilibrium constant(K) for the aforesaid chemical reaction is :
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Nov
In a chemical reaction, A + 2B (K) ⇋ 2C + D, the initial concentration of B was 1.5 times of the concentration of A, but the equilibrium concentrations of A and B were found to be equal. The equilibrium constant(K) for the aforesaid chemical reaction is : A + 2B (K) ⇋ 2C + [...]
Posted in: Chapter 7 - Equilibrium , Chemistry , JEE Adv and Mains Chemistry 41 Years Solved Video Solutions 1979 - 2019 ,
Tags: A + 2B (K) ⇋ 2C + D , but the equilibrium concentrations of A and B were found to be equal. The equilibrium constant(K) for the aforesaid chemical reaction is : , In a chemical reaction , the initial concentration of B was 1.5 times of the concentration of A ,
For the following reactions, equilibrium constants are given : S(s)+O2(g)⇌SO2(g);K1=10^52 2S(s)+3O2(g)⇌2SO3(g);K2=10^129 The equilibrium constant for the reaction, 2SO2(g)+O2(g)⇌2SO3(g) is :
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Nov
For the following reactions, equilibrium constants are given : S(s)+O2(g)⇌SO2(g);K1=10^52 2S(s)+3O2(g)⇌2SO3(g);K2=10^129 The equilibrium constant for the reaction, 2SO2(g)+O2(g)⇌2SO3(g) is : 2SO2(g)+O2(g)⇌2SO3(g) is : equilibrium constants are given : S(s)+O2(g)⇌SO2(g);K1=10^52 2S(s)+3O2(g)⇌2SO3(g);K2=10^129 The equilibrium constant for the reaction For the following reactions November 16, 2020 Category: Chapter 7 - Equilibrium , Chemistry , JEE Adv and Mains [...]
Posted in: Chapter 7 - Equilibrium , Chemistry , JEE Adv and Mains Chemistry 41 Years Solved Video Solutions 1979 - 2019 ,
Tags: 2SO2(g)+O2(g)⇌2SO3(g) is : , equilibrium constants are given : S(s)+O2(g)⇌SO2(g);K1=10^52 2S(s)+3O2(g)⇌2SO3(g);K2=10^129 The equilibrium constant for the reaction , For the following reactions ,
For the reaction, 2SO2(g)+O2(g)↽−−⇀2SO3(g), ΔH = −57⋅2 kJ mol^−1 and Kc = 1.7×10^16. Which of the following statement is INCORRECT?
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Nov
For the reaction, 2SO2(g)+O2(g)↽−−⇀2SO3(g), ΔH = −57⋅2 kJ mol^−1 and Kc = 1.7×10^16. Which of the following statement is INCORRECT? 2SO2(g)+O2(g)↽−−⇀2SO3(g) For the reaction ΔH = −57⋅2 kJ mol^−1 and Kc = 1.7×10^16. Which of the following statement is INCORRECT? November 16, 2020 Category: Chapter 7 - Equilibrium , Chemistry , JEE Adv and Mains [...]
Posted in: Chapter 7 - Equilibrium , Chemistry , JEE Adv and Mains Chemistry 41 Years Solved Video Solutions 1979 - 2019 ,
Tags: 2SO2(g)+O2(g)↽−−⇀2SO3(g) , For the reaction , ΔH = −57⋅2 kJ mol^−1 and Kc = 1.7×10^16. Which of the following statement is INCORRECT? ,
In which one of the following equilibria, Kp ≠ Kc ?
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Nov
In which one of the following equilibria, Kp ≠ Kc ? In which one of the following equilibria Kp ≠ Kc ? November 16, 2020 Category: Chapter 7 - Equilibrium , Chemistry , JEE Adv and Mains Chemistry 41 Years Solved Video Solutions 1979 - 2019 ,
Posted in: Chapter 7 - Equilibrium , Chemistry , JEE Adv and Mains Chemistry 41 Years Solved Video Solutions 1979 - 2019 ,
Tags: In which one of the following equilibria , Kp ≠ Kc ? ,
The incorrect match in the following is :
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Nov
The incorrect match in the following is : The incorrect match in the following is : November 16, 2020 Category: Chapter 7 - Equilibrium , Chemistry , JEE Adv and Mains Chemistry 41 Years Solved Video Solutions 1979 - 2019 ,
Posted in: Chapter 7 - Equilibrium , Chemistry , JEE Adv and Mains Chemistry 41 Years Solved Video Solutions 1979 - 2019 ,
Tags: The incorrect match in the following is : ,