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Which is the best description of the behaviour of bromine in the reaction given below H2O +Br2 gives HOBr + HBr
22
Nov
Which is the best description of the behaviour of bromine in the reaction given below H2O +Br2 gives HOBr + HBr Which is the best description of the behaviour of bromine in the reaction given below H2O +Br2 gives HOBr + HBr November 22, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP [...]
1.0 L solution is prepared by mixing 61 g benzoic acid (pKa=4.2) with 72 g of sodium benzoate and then 300 mL 1.0 M HBr solution was added. The pH of final solution is :
22
Nov
1.0 L solution is prepared by mixing 61 g benzoic acid (pKa=4.2) with 72 g of sodium benzoate and then 300 mL 1.0 M HBr solution was added. The pH of final solution is : 1.0 L solution is prepared by mixing 61 g benzoic acid (pKa=4.2) with 72 g of sodium benzoate and then [...]
THe oxide which cannot act as a reducing agent is (a) SO2 (b) NO2 (c0 CO2 (d) CLO2
22
Nov
THe oxide which cannot act as a reducing agent is (a) SO2 (b) NO2 (c0 CO2 (d) CLO2 THe oxide which cannot act as a reducing agent is (a) SO2 (b) NO2 (c0 CO2 (d) CLO2 November 22, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
Show that the square of an odd positive integers is of the form 8m+1 for some whole number m.
22
Nov
Show that the square of an odd positive integers is of the form 8m+1 for some whole number m. Show that the square of an odd positive integers is of the form 8m+1 for some whole number m. November 22, 2020 Category: Chapter 1 - Real Numbers , Maths , NCERT Class 10 ,
Using Euclid’s division algorithm, find which of the following pairs of numbers are co-primes :
22
Nov
Using Euclid’s division algorithm, find which of the following pairs of numbers are co-primes : find which of the following pairs of numbers are co-primes : Using Euclid’s division algorithm November 22, 2020 Category: Chapter 1 - Real Numbers , Maths , NCERT Class 10 ,
Which substance is serving as a reducing agent in the following reaction 14 H + Cr2O7^2- +3Ni gives 2Cr^3 + 7H2O + 3Ni^2
22
Nov
Which substance is serving as a reducing agent in the following reaction 14 H + Cr2O7^2- +3Ni gives 2Cr^3 + 7H2O + 3Ni^2 Which substance is serving as a reducing agent in the following reaction 14 H + Cr2O7^2- +3Ni gives 2Cr^3 + 7H2O + 3Ni^2 November 22, 2020 Category: Uncategorised (JEE Advanced Physics by [...]
Consider the charge in oxidation state of Bomine correspnding to different emf values as shown in the diagram below
22
Nov
Consider the charge in oxidation state of Bomine correspnding to different emf values as shown in the diagram below Consider the charge in oxidation state of Bomine correspnding to different emf values as shown in the diagram below November 22, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
Using Euclid’s division algorithm, find which of the following pairs of numbers are co-primes :
22
Nov
Using Euclid’s division algorithm, find which of the following pairs of numbers are co-primes : find which of the following pairs of numbers are co-primes : Using Euclid’s division algorithm November 22, 2020 Category: Chapter 1 - Real Numbers , Maths , NCERT Class 10 ,
Assertion : 22.4 L of N2 at NTP and 5.6 L O2 at NTO contain equal number of molecules. Reason : under similar condition of temperature and pressurre all gases contains equal number of molecules.
22
Nov
Assertion : 22.4 L of N2 at NTP and 5.6 L O2 at NTO contain equal number of molecules. Reason : under similar condition of temperature and pressurre all gases contains equal number of molecules. Assertion : 22.4 L of N2 at NTP and 5.6 L O2 at NTO contain equal number of molecules. Reason [...]
Can the number 6^n, n being a natural number, end with digit 5 ? Give reasons.
22
Nov
Can the number 6^n, n being a natural number, end with digit 5 ? Give reasons. Can the number 6^n end with digit 5 ? Give reasons. n being a natural number November 22, 2020 Category: Chapter 1 - Real Numbers , Maths , NCERT Class 10 ,