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Nitric oxide reacts with bromine and gives nitrosyl-bromide as per reaction given below: 2NO(g)+Br2(g)⇔2NOBr(g). When 0.087mole of NO and 0.0437mole of Br2 are mixed in a closed container at constant temperature, 0.0518mole of NOBr is obtained at equilibrium. Calculate equilibrium amount of nitric oxide and bromine.
22
Nov
Nitric oxide reacts with bromine and gives nitrosyl-bromide as per reaction given below: 2NO(g)+Br2(g)⇔2NOBr(g). When 0.087mole of NO and 0.0437mole of Br2 are mixed in a closed container at constant temperature, 0.0518mole of NOBr is obtained at equilibrium. Calculate equilibrium amount of nitric oxide and bromine. For the following equilibrium for the reverse reaction? KC [...]
Reaction between nitrogen and oxygen takes place as following: 2N2(g)+O2⇔2N2O(g) If a mixture of 0.482 mole N2 and 0.933 mole of O2 is placed in a reaction vessel of volume 10 litre and allowed to form N2O at a temperature for which Kc=2.0 × 10^−37 litre mol^−1. Determine the composition of equilibrium mixture.
22
Nov
Reaction between nitrogen and oxygen takes place as following: 2N2(g)+O2⇔2N2O(g) If a mixture of 0.482 mole N2 and 0.933 mole of O2 is placed in a reaction vessel of volume 10 litre and allowed to form N2O at a temperature for which Kc=2.0 × 10^−37 litre mol^−1. Determine the composition of equilibrium mixture. For the [...]
Explain why pure liquids and solids can be ignored while writing the equilibrium constant expression.
22
Nov
Explain why pure liquids and solids can be ignored while writing the equilibrium constant expression. Explain why pure liquids and solids can be ignored while writing the equilibrium constant expression. November 22, 2020 Category: Chapter 7 - Equilibrium , Chemistry , NCERT Exemplar Class 11 ,
Find out the value of Kc for each of the following equilibria from the value of Kp (a)2NOCl(g)⇔2NO(g)+Cl2(g),Kp=1⋅8×10−2 at 500 K (b) CaCO3(s)⇔CaO(s) ⇔ CaO(s) + CO2(g), Kp=167at1073K.
22
Nov
Find out the value of Kc for each of the following equilibria from the value of Kp (a)2NOCl(g)⇔2NO(g)+Cl2(g),Kp=1⋅8×10−2 at 500 K (b) CaCO3(s)⇔CaO(s) ⇔ CaO(s) + CO2(g), Kp=167at1073K. Find out the value of Kc for each of the following equilibria from the value of Kp (a)2NOCl(g)⇔2NO(g)+Cl2(g) Kp=1⋅8×10−2 at 500 K (b) CaCO3(s)⇔CaO(s) ⇔ CaO(s) + [...]
For the following equilibrium, KC =6.3×10 14 at 1000K. NO(g)+O 3(g)⇌NO2(g)+O2 (g). Both the forward and reverse reactions in the equilibrium are elementary bimolecular reactions. What is KC , for the reverse reaction?
22
Nov
For the following equilibrium, KC =6.3×10 14 at 1000K. NO(g)+O 3(g)⇌NO2(g)+O2 (g). Both the forward and reverse reactions in the equilibrium are elementary bimolecular reactions. What is KC , for the reverse reaction? For the following equilibrium for the reverse reaction? KC =6.3×10 14 at 1000K. NO(g)+O 3(g)⇌NO2(g)+O2 (g). Both the forward and reverse reactions [...]
Write the expression for the equilibrium constant, Kc for each of the following reactions.
22
Nov
Write the expression for the equilibrium constant, Kc for each of the following reactions. Kc for each of the following reactions. Write the expression for the equilibrium constant November 22, 2020 Category: Chapter 7 - Equilibrium , Chemistry , NCERT Exemplar Class 11 ,
At a certain temperature and total pressure of 10^ 5 Pa, iodine vapour contains 40% by volume of I atoms. I2(g)⇌2I(g) Calculate Kp for the equilibrium.
22
Nov
At a certain temperature and total pressure of 10^ 5 Pa, iodine vapour contains 40% by volume of I atoms. I2(g)⇌2I(g) Calculate Kp for the equilibrium. At a certain temperature and total pressure of 10^ 5 Pa iodine vapour contains 40% by volume of I atoms. I2(g)⇌2I(g) Calculate Kp for the equilibrium. November 22, 2020 [...]
Graphically, the pair of equations 6x – 3y + 10 = 0 2x – y + 9 = 0 represents two lines which are
22
Nov
Graphically, the pair of equations 6x – 3y + 10 = 0 2x – y + 9 = 0 represents two lines which are Graphically the pair of equations 6x – 3y + 10 = 0 2x – y + 9 = 0 represents two lines which are November 22, 2020 Category: Chapter 3 - [...]
A liquid is in equilibrium with its vapour in a sealed container at a fixed temperature. The volume of the container is suddenly increased.
22
Nov
A liquid is in equilibrium with its vapour in a sealed container at a fixed temperature. The volume of the container is suddenly increased. A liquid is in equilibrium with its vapour in a sealed container at a fixed temperature. The volume of the container is suddenly increased. November 22, 2020 Category: Chapter 7 - [...]
If the remainder on division of x^3 + 2x^2 + kx + 3 by x – 3 is 21, then find the quotient and value of k. Hence, find the zeroes of the cubic polynomial x^3 + 2x^2 + kx – 18.
22
Nov
If the remainder on division of x^3 + 2x^2 + kx + 3 by x – 3 is 21, then find the quotient and value of k. Hence, find the zeroes of the cubic polynomial x^3 + 2x^2 + kx – 18. find the zeroes of the cubic polynomial x^3 + 2x^2 + kx - [...]