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If cosecθ + cotθ = p, then prove that cosθ = P^2−1/P^2+1
25
Nov
If cosecθ + cotθ = p, then prove that cosθ = P^2−1/P^2+1 If cosecθ + cotθ = p then prove that cosθ = P^2−1/P^2+1 November 25, 2020 Category: Chapter 8 - Introduction to Trigonometry , Maths , NCERT Class 10 ,
The chief source of iodine in which it is present as sodium iodate is (a) Sea weeds (b) Caliche (c) Carnallite
25
Nov
The chief source of iodine in which it is present as sodium iodate is (a) Sea weeds (b) Caliche (c) Carnallite The chief source of iodine in which it is present as sodium iodate is (a) Sea weeds (b) Caliche (c) Carnallite November 25, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP [...]
Show that tan^4θ + tan^2θ = sec^4θ – sec^2θ.
25
Nov
Show that tan^4θ + tan^2θ = sec^4θ – sec^2θ. Show that tan^4θ + tan^2θ = sec^4θ – sec^2θ. November 25, 2020 Category: Chapter 8 - Introduction to Trigonometry , Maths , NCERT Class 10 ,
On exciting Cl2 molecule by UV light, we get (a) Cl (b) Cl+ (c) Cl- (d) All
25
Nov
On exciting Cl2 molecule by UV light, we get (a) Cl (b) Cl+ (c) Cl- (d) All On exciting Cl2 molecule by UV light we get (a) Cl (b) Cl+ (c) Cl- (d) All November 25, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
If I2 is dissolved in aqueous KI, the intense yellow species I3-, is formed. The structure of I3- ions is (a) Square pyramidal (b) Trigonal bipyramidal
25
Nov
If I2 is dissolved in aqueous KI, the intense yellow species I3-, is formed. The structure of I3- ions is (a) Square pyramidal (b) Trigonal bipyramidal If I2 is dissolved in aqueous KI is formed. The structure of I3- ions is (a) Square pyramidal (b) Trigonal bipyramidal the intense yellow species I3- November 25, 2020 [...]
For N3- > O2- > F- and Na+, the order in which their ionic radii varies is
25
Nov
For N3- > O2- > F- and Na+, the order in which their ionic radii varies is For N3- > O2- > F- and Na+ the order in which their ionic radii varies is November 25, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
An observer 1.5 metres tall is 20.5 metres away from a tower 22 metres high. Determine the angle of elevation of the top of the tower from the eye of the observer.
25
Nov
An observer 1.5 metres tall is 20.5 metres away from a tower 22 metres high. Determine the angle of elevation of the top of the tower from the eye of the observer. An observer 1.5 metres tall is 20.5 metres away from a tower 22 metres high. Determine the angle of elevation of the top [...]
Show that cos^2 (45 degree + θ) + cos^2 (45 degree – θ)/ tan (60 degree + θ) tan (30 degree – θ) = 1
25
Nov
Show that cos^2 (45 degree + θ) + cos^2 (45 degree – θ)/ tan (60 degree + θ) tan (30 degree – θ) = 1 Show that cos^2 (45 degree + θ) + cos^2 (45 degree - θ)/ tan (60 degree + θ) tan (30 degree - θ) = 1 November 25, 2020 Category: Chapter [...]
Chlorine gas reacts with red hot calcium oxide to give (a) Bleaching powder and dichlorine monoxide (b) Bleaching powder and water
25
Nov
Chlorine gas reacts with red hot calcium oxide to give (a) Bleaching powder and dichlorine monoxide (b) Bleaching powder and water Chlorine gas reacts with red hot calcium oxide to give (a) Bleaching powder and dichlorine monoxide (b) Bleaching powder and water November 25, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP [...]
If 2sin^2θ – cos^2θ = 2, then find the value of θ.
25
Nov
If 2sin^2θ – cos^2θ = 2, then find the value of θ. If 2sin^2θ – cos^2θ = 2 then find the value of θ. November 25, 2020 Category: Chapter 8 - Introduction to Trigonometry , Maths , NCERT Class 10 ,