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The mass of a photon with a wavelength equal to 1.54 x 10^-8 cm is
27
Nov
The mass of a photon with a wavelength equal to 1.54 x 10^-8 cm is The mass of a photon with a wavelength equal to 1.54 x 10^-8 cm is November 27, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
Posted in: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
Tags: The mass of a photon with a wavelength equal to 1.54 x 10^-8 cm is ,
If the acceleration of wedge in the shown arrangement is a ms−2 towards left, then at this instant, acceleration of the block (magnitude only) would be
27
Nov
If the acceleration of wedge in the shown arrangement is a ms−2 towards left, then at this instant, acceleration of the block (magnitude only) would be acceleration of the block (magnitude only) would be If the acceleration of wedge in the shown arrangement is a ms−2 towards left then at this instant November 27, 2020 [...]
Posted in: Cengage JEE Mains Physics by B.M Sharma , Chapter 5 - Newton's Laws of Motion (Without Friction) , Chapter 6 - Newton's Laws of Motion (With Friction) and Dynamics of Circular Motion ,
Tags: acceleration of the block (magnitude only) would be , If the acceleration of wedge in the shown arrangement is a ms−2 towards left , then at this instant ,
in the arrangement shown in fig.4.191 at a particular instant.the roller is coming down with a speed of 12ms-1 and C is moving up with 4ms-1.as the same instant it is also known that w.r.t pulley p block A IS MOVING down with speed 3ms-1 determine the motion of block b (velocity)w.r.t ground
27
Nov
in the arrangement shown in fig.4.191 at a particular instant.the roller is coming down with a speed of 12ms-1 and C is moving up with 4ms-1.as the same instant it is also known that w.r.t pulley p block A IS MOVING down with speed 3ms-1 determine the motion of block b (velocity)w.r.t ground A uniform [...]
Posted in: Cengage JEE Mains Physics by B.M Sharma , Chapter 5 - Newton's Laws of Motion (Without Friction) , Chapter 6 - Newton's Laws of Motion (With Friction) and Dynamics of Circular Motion ,
Tags: A uniform rod of mass 2M is bent into four adjacent semicircles each of radius r , all lying in the same plane. The moment of inertia of the bent rod about an axis through one end A and perpendicular to plane of rod is. ,
The specific charge of proton is 9.6 x 10^7 C/kg then for an alpha particle it will be
27
Nov
The specific charge of proton is 9.6 x 10^7 C/kg then for an alpha particle it will be The specific charge of proton is 9.6 x 10^7 C/kg then for an alpha particle it will be November 27, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
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Tags: The specific charge of proton is 9.6 x 10^7 C/kg then for an alpha particle it will be ,
For the pulley system shown in Fig4.181 each of the cables at A and B is given a velocity of 2ms−1 in the direction of the arrow. Determine the upward velocity v of the load m.
27
Nov
For the pulley system shown in Fig4.181 each of the cables at A and B is given a velocity of 2ms−1 in the direction of the arrow. Determine the upward velocity v of the load m. For the pulley system shown in Fig4.181 each of the cables at A and B is given a velocity [...]
Posted in: Cengage JEE Mains Physics by B.M Sharma , Chapter 5 - Newton's Laws of Motion (Without Friction) , Chapter 6 - Newton's Laws of Motion (With Friction) and Dynamics of Circular Motion ,
Tags: For the pulley system shown in Fig4.181 each of the cables at A and B is given a velocity of 2ms−1 in the direction of the arrow. Determine the upward velocity v of the load m. ,
Nitrogen is liberated by the thermal decomposition of only (a) NH4NO2 (b) NaN3 (c) (NH4)2Cr2O7 (d) All of three
27
Nov
Nitrogen is liberated by the thermal decomposition of only (a) NH4NO2 (b) NaN3 (c) (NH4)2Cr2O7 (d) All of three Nitrogen is liberated by the thermal decomposition of only (a) NH4NO2 (b) NaN3 (c) (NH4)2Cr2O7 (d) All of three November 27, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
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Tags: Nitrogen is liberated by the thermal decomposition of only (a) NH4NO2 (b) NaN3 (c) (NH4)2Cr2O7 (d) All of three ,
As shown in fig, if acceleration of M with respect to ground is 2ms−2 , then
27
Nov
As shown in fig, if acceleration of M with respect to ground is 2ms−2 , then as shown in fig. if acceleration of M with respect to ground is 2ms−2 then November 27, 2020 Category: Cengage JEE Mains Physics by B.M Sharma , Chapter 5 - Newton's Laws of Motion (Without Friction) , Chapter 6 [...]
Posted in: Cengage JEE Mains Physics by B.M Sharma , Chapter 5 - Newton's Laws of Motion (Without Friction) , Chapter 6 - Newton's Laws of Motion (With Friction) and Dynamics of Circular Motion ,
Tags: as shown in fig. , if acceleration of M with respect to ground is 2ms−2 , then ,
When AgNO3 is heated strongly, the products formed are (a) NO and NO2 (b) NO2 and O2 (c) NO2 and N2O
27
Nov
When AgNO3 is heated strongly, the products formed are (a) NO and NO2 (b) NO2 and O2 (c) NO2 and N2O the products formed are (a) NO and NO2 (b) NO2 and O2 (c) NO2 and N2O When AgNO3 is heated strongly November 27, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP [...]
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Tags: the products formed are (a) NO and NO2 (b) NO2 and O2 (c) NO2 and N2O , When AgNO3 is heated strongly ,
Blocks A and C start from rest and move to the right with acceleration A​=12t ms−2 and Ac​=3ms−2. Here t is in seconds. The time when block B again comes to rest is
27
Nov
Blocks A and C start from rest and move to the right with acceleration A​=12t ms−2 and Ac​=3ms−2. Here t is in seconds. The time when block B again comes to rest is Blocks A and C start from rest and move to the right with acceleration A​=12t ms−2 and Ac​=3ms−2. Here t is in [...]
Posted in: Cengage JEE Mains Physics by B.M Sharma , Chapter 5 - Newton's Laws of Motion (Without Friction) , Chapter 6 - Newton's Laws of Motion (With Friction) and Dynamics of Circular Motion ,
Tags: Blocks A and C start from rest and move to the right with acceleration A​=12t ms−2 and Ac​=3ms−2. Here t is in seconds. The time when block B again comes to rest is ,
Potash alum is a (a) Complex salt (b) Acid salt (c) Double salt (d) Normal salt
27
Nov
Potash alum is a (a) Complex salt (b) Acid salt (c) Double salt (d) Normal salt Potash alum is a (a) Complex salt (b) Acid salt (c) Double salt (d) Normal salt November 27, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
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Tags: Potash alum is a (a) Complex salt (b) Acid salt (c) Double salt (d) Normal salt ,