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The bond angle in PH3 is (a) MUch less than NH3 (b) Equal to that of NH3 (c) Much greater than NH3 (d) slightly greater than NH3
06
Dec
The bond angle in PH3 is (a) MUch less than NH3 (b) Equal to that of NH3 (c) Much greater than NH3 (d) slightly greater than NH3 The bond angle in PH3 is (a) MUch less than NH3 (b) Equal to that of NH3 (c) Much greater than NH3 (d) slightly greater than NH3 December [...]
In benzene , all the six C – C bonds have the same length because of (a) Tautomerism (b) sp^2 hybridisation (c) Isomerism (d) Inductive effect
06
Dec
In benzene , all the six C – C bonds have the same length because of (a) Tautomerism (b) sp^2 hybridisation (c) Isomerism (d) Inductive effect all the six C - C bonds have the same length because of (a) Tautomerism (b) sp^2 hybridisation (c) Isomerism (d) Inductive effect In benzene December 6, 2020 Category: [...]
Which of the following doesn’t give a ppt. with silver nitrate solution (a) Ethyl bromide (b) Sodium bromide (c) Calcium chloride (d) Sodium chloride
06
Dec
Which of the following doesn’t give a ppt. with silver nitrate solution (a) Ethyl bromide (b) Sodium bromide (c) Calcium chloride (d) Sodium chloride Which of the following doesn't give a ppt. with silver nitrate solution (a) Ethyl bromide (b) Sodium bromide (c) Calcium chloride (d) Sodium chloride December 6, 2020 Category: Uncategorised (JEE Advanced [...]
Which reagent is used to remove SO4 2- and Cl- (a) BaSO4 (b) NaOH (c) Pb(NO3)2 (d) KOH
06
Dec
Which reagent is used to remove SO4 2- and Cl- (a) BaSO4 (b) NaOH (c) Pb(NO3)2 (d) KOH Which reagent is used to remove SO4 2- and Cl- (a) BaSO4 (b) NaOH (c) Pb(NO3)2 (d) KOH December 6, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
A white sodium salt dissolves readily in water to give a solution which is neutral to litmus. When silver nitrate solution is added to the solution, a white precipitate is formed which does not dissolve in dilute nitric acid.
06
Dec
A white sodium salt dissolves readily in water to give a solution which is neutral to litmus. When silver nitrate solution is added to the solution, a white precipitate is formed which does not dissolve in dilute nitric acid. a white precipitate is formed which does not dissolve in dilute nitric acid. A white sodium [...]
By passing H2S gas in acidified KMnO4 solution, we get (a) K2S (b) S (c) K2SO3 (d) MnO2
06
Dec
By passing H2S gas in acidified KMnO4 solution, we get (a) K2S (b) S (c) K2SO3 (d) MnO2 By passing H2S gas in acidified KMnO4 solution we get (a) K2S (b) S (c) K2SO3 (d) MnO2 December 6, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
Which of the following will be octahedral (a) SF6 (b) BF4^- (c) PCL5 (d) BO3^3-
06
Dec
Which of the following will be octahedral (a) SF6 (b) BF4^- (c) PCL5 (d) BO3^3- Which of the following will be octahedral (a) SF6 (b) BF4^- (c) PCL5 (d) BO3^3- December 6, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
Which of the following precipitate does not dissolve even in large excess of NH4OH (a) AgCl (b) AgBr (c) AgI (d) None of these
06
Dec
Which of the following precipitate does not dissolve even in large excess of NH4OH (a) AgCl (b) AgBr (c) AgI (d) None of these Which of the following precipitate does not dissolve even in large excess of NH4OH (a) AgCl (b) AgBr (c) AgI (d) None of these December 6, 2020 Category: Uncategorised (JEE Advanced [...]
Which one is false in the following statements (a) each carbon in ethylene is in sp^2 hybridisation (b) each carbon in acetylene is in sp^3 hybridisation (c) each carbon in bezene is in sp^2 hybridisation (d) each carbon in ethane is in sp^3 hybridisation
06
Dec
Which one is false in the following statements (a) each carbon in ethylene is in sp^2 hybridisation (b) each carbon in acetylene is in sp^3 hybridisation (c) each carbon in bezene is in sp^2 hybridisation (d) each carbon in ethane is in sp^3 hybridisation Hybridisation shown by N in HNO3 is (a) sp^2 (b) sp^3d [...]
The PCL5 molecule is a result of the hybridisation of (a) sp^2d^2 (b) sp^3d (c) spd^3 (d) sp^2d^3
06
Dec
The PCL5 molecule is a result of the hybridisation of (a) sp^2d^2 (b) sp^3d (c) spd^3 (d) sp^2d^3 The PCL5 molecule is a result of the hybridisation of (a) sp^2d^2 (b) sp^3d (c) spd^3 (d) sp^2d^3 December 6, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,