Physics
A particle moves a distance x in time t according to equation x = (t + 5)^−1. The acceleration of particle is proportional to
27
Aug
A particle moves a distance x in time t according to equation x = (t + 5)^−1. The acceleration of particle is proportional to A particle moves a distance x in time t according to equation x = (t + 5)^−1. The acceleration of particle is proportional to August 27, 2020 Category: Chapter 3 - [...]
A ball is dropped from a high rise platform at t = 0 starting from rest. After 6 seconds another ball is thrown downwards from the same platform with a speed v. The two balls meet at t=18 s. What is the value of v? (Take g=10m/s^2)
27
Aug
A ball is dropped from a high rise platform at t = 0 starting from rest. After 6 seconds another ball is thrown downwards from the same platform with a speed v. The two balls meet at t=18 s. What is the value of v? (Take g=10m/s^2) The motion of a particle along a straight [...]
A boy standing at the top of a tower of 20 m height drops a stone. Assuming g = 10ms^−2, the velocity with which it hits the ground is:
27
Aug
A boy standing at the top of a tower of 20 m height drops a stone. Assuming g = 10ms^−2, the velocity with which it hits the ground is: A boy standing at the top of a tower of 20 m height drops a stone. Assuming g = 10ms^−2 the velocity with which it hits [...]
The motion of a particle along a straight line is described by equation x = 8 + 12 t – t^3 where x is in metre and t in second. The retardation of the particle when its velocity becomes zero is
27
Aug
The motion of a particle along a straight line is described by equation x = 8 + 12 t – t^3 where x is in metre and t in second. The retardation of the particle when its velocity becomes zero is The motion of a particle along a straight line is described by equation x [...]
A stone falls freely under gravity. It covers distances h1,h2 and h3 in the first 5 seconds, the next 5 seconds and the next 5 seconds respectively. The relation between h1,h2 and h3 is
27
Aug
A stone falls freely under gravity. It covers distances h1,h2 and h3 in the first 5 seconds, the next 5 seconds and the next 5 seconds respectively. The relation between h1,h2 and h3 is A stone falls freely under gravity. It covers distances h1 h2 and h3 in the first 5 seconds h2 and h3 [...]
A particle of unit mass undergoes one-dimensional motion such that its velocity varies according to v(x) = βx − 2n, where β and n are constants and x is the position of the particle. The acceleration of the particle as a function of x, is given by
27
Aug
A particle of unit mass undergoes one-dimensional motion such that its velocity varies according to v(x) = βx − 2n, where β and n are constants and x is the position of the particle. The acceleration of the particle as a function of x, is given by A particle of unit mass undergoes one-dimensional motion [...]
Two cars P and Q starts from a point at the same time in a straight line and their positions are represents by xp(t) = at + bt^2 and xQ (t) = ft − t^2. At what time do the cars have the same velocity?
27
Aug
Two cars P and Q starts from a point at the same time in a straight line and their positions are represents by xp(t) = at + bt^2 and xQ (t) = ft − t^2. At what time do the cars have the same velocity? if she remains stationary on the moving escalator Preeti reached [...]
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Chapter 3 - Motion in a Straight Line
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if she remains stationary on the moving escalator ,
Preeti reached the metro station and found that the escalator was not working. She walked up the stationary escalator in time t1. On other days ,
then the escalator takes her up in time t2. The time taken by her walk up on the moving escalator will be: ,
If the velocity of a particle is v = At + Bt^2, where A and B are constants, then the distance travelled by it between 1 s and 2 s is
27
Aug
If the velocity of a particle is v = At + Bt^2, where A and B are constants, then the distance travelled by it between 1 s and 2 s is If the velocity of a particle is v = At + Bt^2 then the distance travelled by it between 1 s and 2 s [...]
Preeti reached the metro station and found that the escalator was not working. She walked up the stationary escalator in time t1. On other days, if she remains stationary on the moving escalator, then the escalator takes her up in time t2. The time taken by her walk up on the moving escalator will be:
27
Aug
Preeti reached the metro station and found that the escalator was not working. She walked up the stationary escalator in time t1. On other days, if she remains stationary on the moving escalator, then the escalator takes her up in time t2. The time taken by her walk up on the moving escalator will be: [...]
Posted in:
Chapter 3 - Motion in a Straight Line
,
NEET Last 32 Years Solved 1988 - 2019 Physics and Chemistry Video Solutions
,
Physics
,
Tags:
if she remains stationary on the moving escalator ,
Preeti reached the metro station and found that the escalator was not working. She walked up the stationary escalator in time t1. On other days ,
then the escalator takes her up in time t2. The time taken by her walk up on the moving escalator will be: ,
A particle moving with velocity bar V is acted by three forces shown by the vector triangle PQR. The velocity of the particle will :
27
Aug
A particle moving with velocity bar V is acted by three forces shown by the vector triangle PQR. The velocity of the particle will : A particle moving with velocity bar V is acted by three forces shown by the vector triangle PQR. The velocity of the particle will : August 27, 2020 Category: Chapter [...]