Chapter 5 – Work, Energy and Power
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A body constrained to move along the z-axis of a coordinate system is subject to a constant force F given by F = – i ^ + 2 j ^ + 3 k ^ N where i ^ , j ^, k ^ are unit vectors along the x, y and z-axis of the system respectively. What is the work done by this force in moving the body a distance of 4 m along the z-axis ?
30
Oct
A body constrained to move along the z-axis of a coordinate system is subject to a constant force F given by F = – i ^ + 2 j ^ + 3 k ^ N where i ^ , j ^, k ^ are unit vectors along the x, y and z-axis of the system [...]
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A body constrained to move along the z-axis of a coordinate system is subject to a constant force F given by F = - i ^ + 2 j ^ + 3 k ^ N where i ^ ,
j ^ ,
k ^ are unit vectors along the x- ,
y- and z-axis of the system respectively. What is the work done by this force in moving the body a distance of 4 m along the z-axis ? ,
A body is moving unidirectionally under the influence of a source of constant power. Its displacement in time t is proportional to
30
Oct
A body is moving unidirectionally under the influence of a source of constant power. Its displacement in time t is proportional to A body is moving unidirectionally under the influence of a source of constant power. Its displacement in time t is proportional to October 30, 2020 Category: Chapter 5 - Work, Energy and Power [...]
A body is initially at rest. It undergoes one-dimensional motion with constant acceleration. The power delivered to it at time t is proportional to
30
Oct
A body is initially at rest. It undergoes one-dimensional motion with constant acceleration. The power delivered to it at time t is proportional to A body is initially at rest. It undergoes one-dimensional motion with constant acceleration. The power delivered to it at time t is proportional to October 30, 2020 Category: Chapter 5 - [...]
The potential energy function for a particle executing linear simple harmonic motion is given by V(x) = kx 2 /2, where k is the force constant of the oscillator. For k = 0.5 Nm^−1 , the graph of V(x) versus x is shown in Fig. Show that a particle of total energy 1 J moving under this potential must turn back when it reaches x = ± 2 m.
30
Oct
The potential energy function for a particle executing linear simple harmonic motion is given by V(x) = kx 2 /2, where k is the force constant of the oscillator. For k = 0.5 Nm^−1 , the graph of V(x) versus x is shown in Fig. Show that a particle of total energy 1 J moving [...]
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the graph of V(x) versus x is shown in Fig. Show that a particle of total energy 1 J moving under this potential must turn back when it reaches x = ± 2 m. ,
The potential energy function for a particle executing linear simple harmonic motion is given by V(x) = kx 2 /2 ,
where k is the force constant of the oscillator. For k = 0.5 Nm^−1 ,
Given below are examples of some potential energy functions in one dimension. Mark the total energy of the particle is indicated by a cross on the energy axis. In each case, specify the regions, if any, in which the particle cannot be found for the given energy. Also, indicate the minimum total energy the particle must have in each case. Think of simple physical contexts for which these potential energy shapes are relevant.
30
Oct
Given below are examples of some potential energy functions in one dimension. Mark the total energy of the particle is indicated by a cross on the energy axis. In each case, specify the regions, if any, in which the particle cannot be found for the given energy. Also, indicate the minimum total energy the particle [...]
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Given below are examples of some potential energy functions in one dimension. Mark the total energy of the particle is indicated by a cross on the energy axis. In each case ,
if any ,
in which the particle cannot be found for the given energy. Also ,
indicate the minimum total energy the particle must have in each case. Think of simple physical contexts for which these potential energy shapes are relevant. ,
specify the regions ,
A body of mass 2 kg initially at rest moves under the action of an applied horizontal force of 7 N on a table with coefficient of kinetic friction = 0.1. Compute the (a) work done by the applied force in 10 s. (b) work done by friction in 10 s, (c) work done by the net force on the body in 10 s, (d) change in kinetic energy of the body in 10 s, and interpret your results.
30
Oct
A body of mass 2 kg initially at rest moves under the action of an applied horizontal force of 7 N on a table with coefficient of kinetic friction = 0.1. Compute the (a) work done by the applied force in 10 s. (b) work done by friction in 10 s, (c) work done by [...]
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a motorist follows a track that turns to his left by an angle of 60° after every 500 m. Starting from a given turn ,
On an open ground ,
sixth and eighth turn. Compare the magnitude of the displacement with the total path length covered by the motorist in each case. ,
specify the displacement of the motorist at the third ,