Chemistry
An ion with mass number 37 possesses one unit off negative charge. If the ion contains 11.1% more neutrons than electrons, find the symbol of the ion.
12
Nov
An ion with mass number 37 possesses one unit off negative charge. If the ion contains 11.1% more neutrons than electrons, find the symbol of the ion. An ion with mass number 37 possesses one unit off negative charge. If the ion contains 11.1% more neutrons than electrons find the symbol of the ion. November [...]
An element with mass number 81 contains 31.7% more neutrons as compared to protons. Assign the atomic symbol.
12
Nov
An element with mass number 81 contains 31.7% more neutrons as compared to protons. Assign the atomic symbol. An element with mass number 81 contains 31.7% more neutrons as compared to protons. Assign the atomic symbol. November 12, 2020 Category: Chapter 2 - Atomic Structure , Chemistry , NCERT Exemplar Class 11 ,
A certain particle carries 2.5×10^−16C of static electric charge. Calculate the number of electrons present in it.
12
Nov
A certain particle carries 2.5×10^−16C of static electric charge. Calculate the number of electrons present in it. A certain particle carries 2.5×10^−16C of static electric charge. Calculate the number of electrons present in it. November 12, 2020 Category: Chapter 2 - Atomic Structure , Chemistry , NCERT Exemplar Class 11 ,
The diameter of zinc atom is 2.6Å. Calculate (a) radius of zinc atom in pm and (b) number of atoms present in a length of 1.6 cm if the atoms are arranged side by side lengthwise.
12
Nov
The diameter of zinc atom is 2.6Å. Calculate (a) radius of zinc atom in pm and (b) number of atoms present in a length of 1.6 cm if the atoms are arranged side by side lengthwise. The diameter of zinc atom is 2.6Å. Calculate (a) radius of zinc atom in pm and (b) number of [...]
2×10^8 atoms of carbon are arranged side by side. Calculate the radius of carbon atom if the length of this arrangement is 3.0 cm.
12
Nov
2×10^8 atoms of carbon are arranged side by side. Calculate the radius of carbon atom if the length of this arrangement is 3.0 cm. 2×10^8 atoms of carbon are arranged side by side. Calculate the radius of carbon atom if the length of this arrangement is 3.0 cm. November 12, 2020 Category: Chapter 2 - [...]
If the diameter of a carbon atom is 0.15 nm, calculate the number of carbon atoms which can be placed side by side in a straight line across the length of scale of length 20 cm long.
12
Nov
If the diameter of a carbon atom is 0.15 nm, calculate the number of carbon atoms which can be placed side by side in a straight line across the length of scale of length 20 cm long. calculate the number of carbon atoms which can be placed side by side in a straight line across [...]
Calculate the energy required for the process , He+(g)→He2+(g)+e The ionization energy for the H-atom in the grounds state is 2.18×10^−18J atom^−1.
12
Nov
Calculate the energy required for the process , He+(g)→He2+(g)+e The ionization energy for the H-atom in the grounds state is 2.18×10^−18J atom^−1. Calculate the energy required for the process He+(g)→He2+(g)+e The ionization energy for the H-atom in the grounds state is 2.18×10^−18J atom^−1. November 12, 2020 Category: Chapter 2 - Atomic Structure , Chemistry , [...]
What transition in the hydrogen spectrum would have the same wavelength as the Balmer transition n=4 to n=2 of He⊕ spectrum?
12
Nov
What transition in the hydrogen spectrum would have the same wavelength as the Balmer transition n=4 to n=2 of He⊕ spectrum? What transition in the hydrogen spectrum would have the same wavelength as the Balmer transition n=4 to n=2 of He⊕ spectrum? November 12, 2020 Category: Chapter 2 - Atomic Structure , Chemistry , NCERT [...]
How many electron in an atom may have the following quantum number ? (a) n=4,ms=−1/2 (b) n=3,l=0
12
Nov
How many electron in an atom may have the following quantum number ? (a) n=4,ms=−1/2 (b) n=3,l=0 How many electron in an atom may have the following quantum number ? (a) n=4 l=0 ms=−1/2 (b) n=3 November 12, 2020 Category: Chapter 2 - Atomic Structure , Chemistry , NCERT Exemplar Class 11 ,
Show that the circumference of the Bohr orbit for the hydrogen atom is an integral multiple of the de Broglie wavelength associated with the electron revolving around the orbit.
12
Nov
Show that the circumference of the Bohr orbit for the hydrogen atom is an integral multiple of the de Broglie wavelength associated with the electron revolving around the orbit. Show that the circumference of the Bohr orbit for the hydrogen atom is an integral multiple of the de Broglie wavelength associated with the electron revolving [...]