Chapter 7 – Equilibrium
For the following equilibrium, KC =6.3×10 14 at 1000K. NO(g)+O 3(g)⇌NO2(g)+O2 (g). Both the forward and reverse reactions in the equilibrium are elementary bimolecular reactions. What is KC , for the reverse reaction?
22
Nov
For the following equilibrium, KC =6.3×10 14 at 1000K. NO(g)+O 3(g)⇌NO2(g)+O2 (g). Both the forward and reverse reactions in the equilibrium are elementary bimolecular reactions. What is KC , for the reverse reaction? For the following equilibrium for the reverse reaction? KC =6.3×10 14 at 1000K. NO(g)+O 3(g)⇌NO2(g)+O2 (g). Both the forward and reverse reactions [...]
Write the expression for the equilibrium constant, Kc for each of the following reactions.
22
Nov
Write the expression for the equilibrium constant, Kc for each of the following reactions. Kc for each of the following reactions. Write the expression for the equilibrium constant November 22, 2020 Category: Chapter 7 - Equilibrium , Chemistry , NCERT Exemplar Class 11 ,
At a certain temperature and total pressure of 10^ 5 Pa, iodine vapour contains 40% by volume of I atoms. I2(g)⇌2I(g) Calculate Kp for the equilibrium.
22
Nov
At a certain temperature and total pressure of 10^ 5 Pa, iodine vapour contains 40% by volume of I atoms. I2(g)⇌2I(g) Calculate Kp for the equilibrium. At a certain temperature and total pressure of 10^ 5 Pa iodine vapour contains 40% by volume of I atoms. I2(g)⇌2I(g) Calculate Kp for the equilibrium. November 22, 2020 [...]
A liquid is in equilibrium with its vapour in a sealed container at a fixed temperature. The volume of the container is suddenly increased.
22
Nov
A liquid is in equilibrium with its vapour in a sealed container at a fixed temperature. The volume of the container is suddenly increased. A liquid is in equilibrium with its vapour in a sealed container at a fixed temperature. The volume of the container is suddenly increased. November 22, 2020 Category: Chapter 7 - [...]