NCERT Class 9
5. D, E and F are respectively the mid-points of the sides BC, CA and AB of a ΔABC. Show that (i) BDEF is a parallelogram. (ii) ar(DEF) = ¼ ar(ABC) (iii) ar (BDEF) = ½ ar(ABC)
15
Oct
5. D, E and F are respectively the mid-points of the sides BC, CA and AB of a ΔABC. Show that (i) BDEF is a parallelogram. (ii) ar(DEF) = ¼ ar(ABC) (iii) ar (BDEF) = ½ ar(ABC) 5. D CA and AB of a ΔABC. Show that (i) BDEF is a parallelogram. (ii) ar(DEF) = [...]
4. In Fig. 9.24, ABC and ABD are two triangles on the same base AB. If line- segment CD is bisected by AB at O, show that: ar(ABC) = ar(ABD).
15
Oct
4. In Fig. 9.24, ABC and ABD are two triangles on the same base AB. If line- segment CD is bisected by AB at O, show that: ar(ABC) = ar(ABD). 4. In Fig. 9.24 ABC and ABD are two triangles on the same base AB. If line- segment CD is bisected by AB at O [...]
3. Show that the diagonals of a parallelogram divide it into four triangles of equal area.
15
Oct
3. Show that the diagonals of a parallelogram divide it into four triangles of equal area. 3. Show that the diagonals of a parallelogram divide it into four triangles of equal area. October 15, 2020 Category: Chapter 9 - Areas of Parallelogram and Triangles , Maths , NCERT Class 9 ,
2. In a triangle ABC, E is the mid-point of median AD. Show that ar(BED) = ¼ ar(ABC).
15
Oct
2. In a triangle ABC, E is the mid-point of median AD. Show that ar(BED) = ¼ ar(ABC). 2. In a triangle ABC E is the mid-point of median AD. Show that ar(BED) = ¼ ar(ABC). October 15, 2020 Category: Chapter 9 - Areas of Parallelogram and Triangles , Maths , NCERT Class 9 ,
1. In Fig.9.23, E is any point on median AD of a ΔABC. Show that ar (ABE) = ar(ACE).
15
Oct
1. In Fig.9.23, E is any point on median AD of a ΔABC. Show that ar (ABE) = ar(ACE). 1. In Fig.9.23 E is any point on median AD of a ΔABC. Show that ar (ABE) = ar(ACE). October 15, 2020 Category: Chapter 9 - Areas of Parallelogram and Triangles , Maths , NCERT Class [...]
6. A farmer was having a field in the form of a parallelogram PQRS. She took any point A on RS and joined it to points P and Q. In how many parts the fields is divided? What are the shapes of these parts? The farmer wants to sow wheat and pulses in equal portions of the field separately. How should she do it?
15
Oct
6. A farmer was having a field in the form of a parallelogram PQRS. She took any point A on RS and joined it to points P and Q. In how many parts the fields is divided? What are the shapes of these parts? The farmer wants to sow wheat and pulses in equal portions [...]
5. In Fig. 9.17, PQRS and ABRS are parallelograms and X is any point on side BR. Show that (i) ar (PQRS) = ar (ABRS) (ii) ar (AXS) = ½ ar (PQRS)
15
Oct
5. In Fig. 9.17, PQRS and ABRS are parallelograms and X is any point on side BR. Show that (i) ar (PQRS) = ar (ABRS) (ii) ar (AXS) = ½ ar (PQRS) 5. In Fig. 9.17 PQRS and ABRS are parallelograms and X is any point on side BR. Show that (i) ar (PQRS) = [...]
4. In Fig. 9.16, P is a point in the interior of a parallelogram ABCD. Show that (i) ar(APB) + ar(PCD) = ½ ar(ABCD) (ii) ar(APD) + ar(PBC) = ar(APB) + ar(PCD)
15
Oct
4. In Fig. 9.16, P is a point in the interior of a parallelogram ABCD. Show that (i) ar(APB) + ar(PCD) = ½ ar(ABCD) (ii) ar(APD) + ar(PBC) = ar(APB) + ar(PCD) 4. In Fig. 9.16 P is a point in the interior of a parallelogram ABCD. Show that (i) ar(APB) + ar(PCD) = ½ [...]
3. P and Q are any two points lying on the sides DC and AD respectively of a parallelogram ABCD. Show that ar(APB) = ar(BQC).
15
Oct
3. P and Q are any two points lying on the sides DC and AD respectively of a parallelogram ABCD. Show that ar(APB) = ar(BQC). 3. P and Q are any two points lying on the sides DC and AD respectively of a parallelogram ABCD. Show that ar(APB) = ar(BQC). October 15, 2020 Category: Chapter [...]
2. If E, F, G and H are respectively the mid-points of the sides of a parallelogram ABCD, show that ar (EFGH) = 1/2 ar(ABCD).
15
Oct
2. If E, F, G and H are respectively the mid-points of the sides of a parallelogram ABCD, show that ar (EFGH) = 1/2 ar(ABCD). 2. If E F G and H are respectively the mid-points of the sides of a parallelogram ABCD show that ar (EFGH) = 1/2 ar(ABCD). October 15, 2020 Category: Chapter [...]