Maths
4. BE and CF are two equal altitudes of a triangle ABC. Using RHS congruence rule, prove that the triangle ABC is isosceles.
15
Oct
4. BE and CF are two equal altitudes of a triangle ABC. Using RHS congruence rule, prove that the triangle ABC is isosceles. 4. BE and CF are two equal altitudes of a triangle ABC. Using RHS congruence rule prove that the triangle ABC is isosceles. October 15, 2020 Category: Chapter 7 - Triangles , [...]
3. Two sides AB and BC and median AM of one triangle ABC are respectively equal to sides PQ and QR and median PN of ΔPQR (see Fig. 7.40). Show that: (i) ΔABM =~ ΔPQN (ii) ΔABC =~ ΔPQR
15
Oct
3. Two sides AB and BC and median AM of one triangle ABC are respectively equal to sides PQ and QR and median PN of ΔPQR (see Fig. 7.40). Show that: (i) ΔABM =~ ΔPQN (ii) ΔABC =~ ΔPQR 3. Two sides AB and BC and median AM of one triangle ABC are respectively equal [...]
2. AD is an altitude of an isosceles triangle ABC in which AB = AC. Show that (i) AD bisects BC (ii) AD bisects angle A.
15
Oct
2. AD is an altitude of an isosceles triangle ABC in which AB = AC. Show that (i) AD bisects BC (ii) AD bisects angle A. 2. AD is an altitude of an isosceles triangle ABC in which AB = AC. Show that (i) AD bisects BC (ii) AD bisects angle A. October 15, 2020 [...]
1. ΔABC and ΔDBC are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC (see Fig. 7.39). If AD is extended to intersect BC at P, show that (i) ΔABD =~ ΔACD (ii) ΔABP =~ ΔACP (iii) AP bisects angle A as well as angle D. (iv) AP is the perpendicular bisector of BC.
15
Oct
1. ΔABC and ΔDBC are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC (see Fig. 7.39). If AD is extended to intersect BC at P, show that (i) ΔABD =~ ΔACD (ii) ΔABP =~ ΔACP (iii) AP bisects angle A as well as [...]
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1. ΔABC and ΔDBC are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC (see Fig. 7.39). If AD is extended to intersect BC at P ,
show that (i) ΔABD =~ ΔACD (ii) ΔABP =~ ΔACP (iii) AP bisects angle A as well as angle D. (iv) AP is the perpendicular bisector of BC. ,
8. Show that the angles of an equilateral triangle are 60° each.
15
Oct
8. Show that the angles of an equilateral triangle are 60° each. 8. Show that the angles of an equilateral triangle are 60° each. October 15, 2020 Category: Chapter 7 - Triangles , Maths , NCERT Class 9 ,
7. ABC is a right-angled triangle in which angle A = 90° and angle AB = angle AC. Find angle B and angle C.
15
Oct
7. ABC is a right-angled triangle in which angle A = 90° and angle AB = angle AC. Find angle B and angle C. 7. ABC is a right-angled triangle in which angle A = 90° and angle AB = angle AC. Find angle B and angle C. October 15, 2020 Category: Chapter 7 - [...]
6. ΔABC is an isosceles triangle in which AB = AC. Side BA is produced to D such that AD = AB (see Fig. 7.34). Show that angle BCD is a right angle.
15
Oct
6. ΔABC is an isosceles triangle in which AB = AC. Side BA is produced to D such that AD = AB (see Fig. 7.34). Show that angle BCD is a right angle. 6. ΔABC is an isosceles triangle in which AB = AC. Side BA is produced to D such that AD = AB [...]
5. ABC and DBC are two isosceles triangles on the same base BC (see Fig. 7.33). Show that angle ABD = angle ACD.
15
Oct
5. ABC and DBC are two isosceles triangles on the same base BC (see Fig. 7.33). Show that angle ABD = angle ACD. 5. ABC and DBC are two isosceles triangles on the same base BC (see Fig. 7.33). Show that angle ABD = angle ACD. October 15, 2020 Category: Chapter 7 - Triangles , [...]
4. ABC is a triangle in which altitudes BE and CF to sides AC and AB are equal (see Fig. 7.32). Show that (i) ΔABE ΔACF (ii) AB = AC, i.e., ABC is an isosceles triangle.
15
Oct
4. ABC is a triangle in which altitudes BE and CF to sides AC and AB are equal (see Fig. 7.32). Show that (i) ΔABE ΔACF (ii) AB = AC, i.e., ABC is an isosceles triangle. 4. ABC is a triangle in which altitudes BE and CF to sides AC and AB are equal (see [...]
3. ABC is an isosceles triangle in which altitudes BE and CF are drawn to equal sides AC and AB respectively (see Fig. 7.31). Show that these altitudes are equal.
15
Oct
3. ABC is an isosceles triangle in which altitudes BE and CF are drawn to equal sides AC and AB respectively (see Fig. 7.31). Show that these altitudes are equal. 3. ABC is an isosceles triangle in which altitudes BE and CF are drawn to equal sides AC and AB respectively (see Fig. 7.31). Show [...]