Chapter 9 – Areas of Parallelogram and Triangles
Sahay Sir > Question Answers > NCERT Class 9 > Maths > Chapter 9 - Areas of Parallelogram and Triangles
8. If the medians of a ∆ ABC intersect at G, show that ar (AGB) = ar (AGC) = ar (BGC) = 1/3 ar (ABC)
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Jul
8. If the medians of a ∆ ABC intersect at G, show that ar (AGB) = ar (AGC) = ar (BGC) = 1/3 ar (ABC) 8. If the medians of a ∆ ABC intersect at G show that ar (AGB) = ar (AGC) = ar (BGC) = 1/3 ar (ABC) July 1, 2021 Category: Chapter [...]
7. In Fig. 9.25, ABCDE is any pentagon. BP drawn parallel to AC meets DC produced at P and EQ drawn parallel to AD meets CD produced at Q. Prove that ar (ABCDE) = ar (APQ)
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Jul
7. In Fig. 9.25, ABCDE is any pentagon. BP drawn parallel to AC meets DC produced at P and EQ drawn parallel to AD meets CD produced at Q. Prove that ar (ABCDE) = ar (APQ) 7. In Fig. 9.25 ABCDE is any pentagon. BP drawn parallel to AC meets DC produced at P and [...]
6. In ∆ ABC, if L and M are the points on AB and AC, respectively such that LM || BC. Prove that ar (LOB) = ar (MOC)
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Jul
6. In ∆ ABC, if L and M are the points on AB and AC, respectively such that LM || BC. Prove that ar (LOB) = ar (MOC) 6. In ∆ ABC if L and M are the points on AB and AC respectively such that LM || BC. Prove that ar (LOB) = ar [...]
5. ABCD is a trapezium in which AB || DC, DC = 30 cm and AB = 50 cm. If X and Y are, respectively the mid-points of AD and BC, prove that ar (DCYX) = 7/9 ar (XYBA)
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Jul
5. ABCD is a trapezium in which AB || DC, DC = 30 cm and AB = 50 cm. If X and Y are, respectively the mid-points of AD and BC, prove that ar (DCYX) = 7/9 ar (XYBA) 5. ABCD is a trapezium in which AB || DC DC = 30 cm and AB [...]
4. In Fig. 9.24, CD || AE and CY || BA. Prove that ar (CBX) = ar (AXY)
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Jul
4. In Fig. 9.24, CD || AE and CY || BA. Prove that ar (CBX) = ar (AXY) 4. In Fig. 9.24 CD || AE and CY || BA. Prove that ar (CBX) = ar (AXY) July 1, 2021 Category: Chapter 9 - Areas of Parallelogram and Triangles , Maths , NCERT Class 9 ,
3. The medians BE and CF of a triangle ABC intersect at G. Prove that the area of ∆ GBC = area of the quadrilateral AFGE.
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Jul
3. The medians BE and CF of a triangle ABC intersect at G. Prove that the area of ∆ GBC = area of the quadrilateral AFGE. 3. The medians BE and CF of a triangle ABC intersect at G. Prove that the area of ∆ GBC = area of the quadrilateral AFGE. July 1, 2021 [...]
2. The diagonals of a parallelogram ABCD intersect at a point O. Through O, a line is drawn to intersect AD at P and BC at Q. Show that PQ divides the parallelogram into two parts of equal area.
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Jul
2. The diagonals of a parallelogram ABCD intersect at a point O. Through O, a line is drawn to intersect AD at P and BC at Q. Show that PQ divides the parallelogram into two parts of equal area. 2. The diagonals of a parallelogram ABCD intersect at a point O. Through O a line [...]
1. A point E is taken on the side BC of a parallelogram ABCD. AE and DC are produced to meet at F. Prove that ar (ADF) = ar (ABFC)
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Jul
1. A point E is taken on the side BC of a parallelogram ABCD. AE and DC are produced to meet at F. Prove that ar (ADF) = ar (ABFC) 1. A point E is taken on the side BC of a parallelogram ABCD. AE and DC are produced to meet at F. Prove that [...]
9. If the mid-points of the sides of a quadrilateral are joined in order, prove that the area of the parallelogram so formed will be half of the area of the given quadrilateral (Fig. 9.19). [Hint: Join BD and draw perpendicular from A on BD.]
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Jul
9. If the mid-points of the sides of a quadrilateral are joined in order, prove that the area of the parallelogram so formed will be half of the area of the given quadrilateral (Fig. 9.19). [Hint: Join BD and draw perpendicular from A on BD.] 9. If the mid-points of the sides of a quadrilateral [...]
8. In trapezium ABCD, AB || DC and L is the mid-point of BC. Through L, a line PQ || AD has been drawn which meets AB in P and DC produced in Q (Fig. 9.18). Prove that ar (ABCD) = ar (APQD)
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Jul
8. In trapezium ABCD, AB || DC and L is the mid-point of BC. Through L, a line PQ || AD has been drawn which meets AB in P and DC produced in Q (Fig. 9.18). Prove that ar (ABCD) = ar (APQD) 8. In trapezium ABCD a line PQ || AD has been drawn [...]