Chapter 9 – Areas of Parallelogram and Triangles

In Fig. 9.23, BD || CA, E is mid-point of CA and BD = 1/2 CA. Prove that ar (ABC) = 2ar (DBC)€ BD || CA E is mid-point of CA and BD = 1/2 CA. Prove that ar (ABC) = 2ar (DBC) In Fig. 9.23 July 1, 2021 Category: Chapter 9 - Areas of [...]

In Fig. 9.22, l, m, n, are straight lines such that l || m and n intersects l at P and m at Q. ABCD is a quadrilateral such that its vertex A is on l. The vertices C and D are on m and AD || n. Show that are straight lines such that [...]

In Fig. 9.20, ABCD is a parallelogram. Points P and Q on BC trisects BC in three equal parts. Prove that ar (APQ) = ar (DPQ) = 1/6 ar(ABCD) ABCD is a parallelogram. Points P and Q on BC trisects BC in three equal parts. Prove that ar (APQ) = ar (DPQ) = 1/6 ar(ABCD) [...]

ABCD is a parallelogram and BC is produced to a point Q such that AD = CQ (Fig. 9.10). If AQ intersects DC at P, show that ar (BPC) = ar (DPQ) ABCD is a parallelogram and BC is produced to a point Q such that AD = CQ (Fig. 9.10). If AQ intersects DC [...]

PQRS is a square. T and U are respectively, the mid-points of PS and QR (Fig. 9.9). Find the area of ∆ OTS, if PQ = 8 cm, where O is the point of intersection of TU and QS. if PQ = 8 cm PQRS is a square. T and U are respectively the mid-points [...]

If in Fig. 9.7, PQRS and EFRS are two parallelograms, then ar (MFR) = 1/2 ar (PQRS). If in Fig. 9.7 PQRS and EFRS are two parallelograms then ar (MFR) = 1/2 ar (PQRS). July 1, 2021 Category: Chapter 9 - Areas of Parallelogram and Triangles , Maths , NCERT Class 9 ,

If P is any point on the median AD of a ∆ ABC, then ar (ABP) ≠ ar (ACP). If P is any point on the median AD of a ∆ ABC then ar (ABP) ≠ ar (ACP). July 1, 2021 Category: Chapter 9 - Areas of Parallelogram and Triangles , Maths , NCERT Class [...]

The area of the figure formed by joining the mid-points of the adjacent sides of a rhombus with diagonals 12 cm and 16 cm is The area of the figure formed by joining the mid-points of the adjacent sides of a rhombus with diagonals 12 cm and 16 cm is July 1, 2021 Category: Chapter [...]

10. In Fig. 9.27, ABCD and AEFD are two parallelograms. Prove that ar (PEA) = ar (QFD) [Hint: Join PD]. 10. In Fig. 9.27 ABCD and AEFD are two parallelograms. Prove that ar (PEA) = ar (QFD) [Hint: Join PD]. July 1, 2021 Category: Chapter 9 - Areas of Parallelogram and Triangles , Maths , [...]

9. In Fig. 9.26, X and Y are the mid-points of AC and AB respectively, QP || BC and CYQ and BXP are straight lines. Prove that ar (ABP) = ar (ACQ). 9. In Fig. 9.26 QP || BC and CYQ and BXP are straight lines. Prove that ar (ABP) = ar (ACQ). X and [...]