NCERT Class 10

In Fig.6.63,D is a point on side BC of Delta ABC such that (BD)/(CD)=(AB)/(AC) .Prove that AD is the bisector of /_BAC. D is a point on side BC of Delta ABC such that (BD)/(CD)=(AB)/(AC) .Prove that AD is the bisector of /_BAC. In Fig.6.63 October 5, 2020 Category: Chapter 6 - Triangles , Maths [...]

In fig. 6.62, two chords AB and CD of a circle intersect each other at the point P (when produced) outside the circle. prove that (1) triangle PAC ~ triangle PDB ,(2) PA.PB = PC.PD (2) PA.PB = PC.PD In fig. 6.62 two chords AB and CD of a circle intersect each other at the [...]

In Fig. 6.61, two chords AB and CD intersect each other at the point P. Prove that: (1) triangle APC ~ triangle DPB () AP. PB = CP.DP In Fig. 6.61 two chords AB and CD intersect each other at the point P. Prove that: (1) triangle APC ~ triangle DPB () AP. PB = [...]

Prove that the sum of the squares of the diagonals of parallelogram is equal to the sum of the squares of its sides. Prove that the sum of the squares of the diagonals of parallelogram is equal to the sum of the squares of its sides. October 5, 2020 Category: Chapter 6 - Triangles , [...]

In Fig. 6.60 , AD is a median of a triangle ABC and AM⊥BC . Prove that (i) AC^2 = AD^2 + BC⋅DM + (2/BC)^2 AD is a median of a triangle ABC and AM⊥BC . Prove that (i) AC^2 = AD^2 + BC⋅DM + (2/BC)^2 In Fig. 6.60 October 5, 2020 Category: Chapter 6 [...]

In Fig. 6.59, ABC is a triangle in which ∠ ABC < 90° and AD ⊥ BC. Prove that AC^2 = AB^2 + BC^2 – 2 BC . BD. ABC is a triangle in which ∠ ABC < 90° and AD ⊥ BC. Prove that AC^2 = AB^2 + BC^2 – 2 BC . BD. [...]

In Fig. 6.58, ABC is a triangle in which ∠ ABC > 90° and AD ⊥ CB produced. Prove that AC^2 = AB^2 + BC^2 + 2 BC . BD. ABC is a triangle in which ∠ ABC > 90° and AD ⊥ CB produced. Prove that AC^2 = AB^2 + BC^2 + 2 BC [...]

In fig. 6.57, D is a point on hypotenuse AC of triangle ABC, such that BD perpendicular AC, DM perpendicular BC and DN perpendicular AB. Prove that: (i) DM^2 =DN.MC (ii) DN^2 = DM.AN. D is a point on hypotenuse AC of triangle ABC DM perpendicular BC and DN perpendicular AB. Prove that: (i) DM^2 [...]

In Fig. 6.56, PS is the bisector of ∠ QPR of Δ PQR. Prove that ��/�� = ��/�� In Fig. 6.56 PS is the bisector of ∠ QPR of Δ PQR. Prove that ��/�� = ��/�� October 5, 2020 Category: Chapter 6 - Triangles , Maths , NCERT Class 10 ,

Tick the correct answer and justify: In ΔABC, AB = 6 root3^cm, AC = 12 cm and BC = 6 cm. The angle B is: AB = 6 root3^cm AC = 12 cm and BC = 6 cm. The angle B is: Tick the correct answer and justify: In ΔABC October 5, 2020 Category: Chapter [...]