NCERT Class 10

Determine if the points (1,5),(2,3) and (−2,−11) are collinear , by distance formula. −11) are collinear 2 3) and (−2 5 by distance formula. Determine if the points (1 October 5, 2020 Category: Chapter 7 - Coordinate Geometry , Maths , NCERT Class 10 ,

A town a is located 36 km east and 15 km north of town A. How would you find the distance from town A to B without actually measuring it. Let us see. This situation can be represented graphically as shown in fig. You may use the Pythagoras theorem to calculate this distance. Observe Fig. [...]

Find the distance between the following pairs of points: (a, b) and (−a, −b) −b) b) and (−a Find the distance between the following pairs of points: (a October 5, 2020 Category: Chapter 7 - Coordinate Geometry , Maths , NCERT Class 10 ,

Find the distance between the following pairs of points: (−5, 7) and (−1, 3) 3% 7) and (−1 Find the distance between the following pairs of points: (−5 October 5, 2020 Category: Chapter 7 - Coordinate Geometry , Maths , NCERT Class 10 ,

Find the distance between the following pairs of points (2,3),(4,1) 1 3% 4 Find the distance between the following pairs of points (2 October 5, 2020 Category: Chapter 7 - Coordinate Geometry , Maths , NCERT Class 10 ,

O is any point inside a rectangle ABCD. prove that OB^2 + OD^2 = OA^2 + OC^2. O is any point inside a rectangle ABCD. prove that OB^2 + OD^2 = OA^2 + OC^2. October 5, 2020 Category: Chapter 6 - Triangles , Maths , NCERT Class 10 ,

BL and CM are medians on sides AC and AB of triangle ABC, right angled at A. prove that 4 (BL^2 + CM^2) = 5 BC^2. BL and CM are medians on sides AC and AB of triangle ABC right angled at A. prove that 4 (BL^2 + CM^2) = 5 BC^2. October 5, 2020 [...]

In figure 6.50, if AD ⊥ BC, prove that AB^2 + CD^2 = BD^2 + AC^2. if AD ⊥ BC In figure 6.50 prove that AB^2 + CD^2 = BD^2 + AC^2. October 5, 2020 Category: Chapter 6 - Triangles , Maths , NCERT Class 10 ,

A ladder is placed against a wall such that its foot is at a distance of 2.5 m from the wall and its top reaches a window 6 m above the ground. Find the length of the ladder. A ladder is placed against a wall such that its foot is at a distance of 2.5 [...]

In fig 6.48, angle ACB = 90° and CD is perpendicular to AB. Prove that BC^2/AC^2 = BD/AD. angle ACB = 90° and CD is perpendicular to AB. Prove that BC^2/AC^2 = BD/AD. In fig 6.48 October 5, 2020 Category: Chapter 6 - Triangles , Maths , NCERT Class 10 ,