Maths
Express the trigonometric ratios sin A, sec A and tan A in terms of cot A .
05
Oct
Express the trigonometric ratios sin A, sec A and tan A in terms of cot A . Express the trigonometric ratios sin A sec A and tan A in terms of cot A . October 5, 2020 Category: Chapter 8 - Introduction to Trigonometry , Maths , NCERT Class 10 ,
Express sin 67° + cos 75° in terms of trigonometric ratios of angles between 0° and 45°.
05
Oct
Express sin 67° + cos 75° in terms of trigonometric ratios of angles between 0° and 45°. Express sin 67° + cos 75° in terms of trigonometric ratios of angles between 0° and 45°. October 5, 2020 Category: Chapter 8 - Introduction to Trigonometry , Maths , NCERT Class 10 ,
If A, B and C are interior angles of a triangle ABC, then show that sin(2/B+C) = cos 2/A.
05
Oct
If A, B and C are interior angles of a triangle ABC, then show that sin(2/B+C) = cos 2/A. B and C are interior angles of a triangle ABC If A then show that sin(2/B+C) = cos 2/A. October 5, 2020 Category: Chapter 8 - Introduction to Trigonometry , Maths , NCERT Class 10 ,
If sec 4A = cosec (A – 20°), where 4A is an acute angle, find the value of A.
05
Oct
If sec 4A = cosec (A – 20°), where 4A is an acute angle, find the value of A. find the value of A. If sec 4A = cosec (A – 20°) where 4A is an acute angle October 5, 2020 Category: Chapter 8 - Introduction to Trigonometry , Maths , NCERT Class 10 ,
If tan A = cot B, prove that A + B = 90°
05
Oct
If tan A = cot B, prove that A + B = 90° If tan A = cot B prove that A + B = 90° October 5, 2020 Category: Chapter 8 - Introduction to Trigonometry , Maths , NCERT Class 10 ,
If tan 2A = cot (A – 18°), where 2A is an acute angle, find the value of A.
05
Oct
If tan 2A = cot (A – 18°), where 2A is an acute angle, find the value of A. find the value of A. If tan 2A = cot (A – 18°) where 2A is an acute angle October 5, 2020 Category: Chapter 8 - Introduction to Trigonometry , Maths , NCERT Class 10 ,
Show that : (ii) cos 38° cos 52° – sin 38° sin 52° = 0
05
Oct
Show that : (ii) cos 38° cos 52° – sin 38° sin 52° = 0 Show that : (ii) cos 38° cos 52° – sin 38° sin 52° = 0 October 5, 2020 Category: Chapter 8 - Introduction to Trigonometry , Maths , NCERT Class 10 ,
Show that : (i) tan 48° tan 23° tan 42° tan 67° = 1
05
Oct
Show that : (i) tan 48° tan 23° tan 42° tan 67° = 1 Show that : (i) tan 48° tan 23° tan 42° tan 67° = 1 October 5, 2020 Category: Chapter 8 - Introduction to Trigonometry , Maths , NCERT Class 10 ,
Evaluate : (iv) cosec 31° – sec 59°
05
Oct
Evaluate : (iv) cosec 31° – sec 59° Evaluate : (iv) cosec 31° – sec 59° October 5, 2020 Category: Chapter 8 - Introduction to Trigonometry , Maths , NCERT Class 10 ,
Evaluate : (iii) cos 48° – sin 42°
05
Oct
Evaluate : (iii) cos 48° – sin 42° Evaluate : (iii) cos 48° – sin 42° October 5, 2020 Category: Chapter 8 - Introduction to Trigonometry , Maths , NCERT Class 10 ,