Chapter 6 – Triangles
Sides of triangles are given below. Determine which of them are right triangles. In case of a right triangle, write the length of its hypotenuse. 50 cm, 80 cm, 100 cm
05
Oct
Sides of triangles are given below. Determine which of them are right triangles. In case of a right triangle, write the length of its hypotenuse. 50 cm, 80 cm, 100 cm 100 cm 80 cm Sides of triangles are given below. Determine which of them are right triangles. In case of a right triangle write [...]
Sides of triangles are given below. Determine which of them are right triangles. In case of a right triangle, write the length of its hypotenuse. 3 cm, 8 cm, 6 cm
05
Oct
Sides of triangles are given below. Determine which of them are right triangles. In case of a right triangle, write the length of its hypotenuse. 3 cm, 8 cm, 6 cm 6 cm 8 cm Sides of triangles are given below. Determine which of them are right triangles. In case of a right triangle write [...]
Sides of triangles are given below. Determine which of them are right triangles. In case of a right triangle, write the length of its hypotenuse. 7 cm, 24 cm, 25 cm
05
Oct
Sides of triangles are given below. Determine which of them are right triangles. In case of a right triangle, write the length of its hypotenuse. 7 cm, 24 cm, 25 cm 24 cm 25 cm Sides of triangles are given below. Determine which of them are right triangles. In case of a right triangle write [...]
Sides of two similar triangles are in the ratio 4:9. Areas of these triangles are in the ratio.
05
Oct
Sides of two similar triangles are in the ratio 4:9. Areas of these triangles are in the ratio. Sides of two similar triangles are in the ratio 4:9. Areas of these triangles are in the ratio. October 5, 2020 Category: Chapter 6 - Triangles , Maths , NCERT Class 10 ,
ABC and BDE are two equilateral triangles such that D is the midpoint of BC. Ratio of area of (△ABC) and (△BDE) is:
05
Oct
ABC and BDE are two equilateral triangles such that D is the midpoint of BC. Ratio of area of (△ABC) and (△BDE) is: ABC and BDE are two equilateral triangles such that D is the midpoint of BC. Ratio of area of (△ABC) and (△BDE) is: October 5, 2020 Category: Chapter 6 - Triangles , [...]
Prove that the area of an equilateral triangle described on one side of a square is equal to half the area of the equilateral triangle described on one of its diagonals.
05
Oct
Prove that the area of an equilateral triangle described on one side of a square is equal to half the area of the equilateral triangle described on one of its diagonals. Prove that the area of an equilateral triangle described on one side of a square is equal to half the area of the equilateral [...]
Prove that the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding medians.
05
Oct
Prove that the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding medians. Prove that the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding medians. October 5, 2020 Category: Chapter 6 - Triangles , [...]
D, E and F are respectively the midpoints of sides ab BC and CA of triangle ABC find the ratio of the areas of triangle DEF in triangle ABC.
05
Oct
D, E and F are respectively the midpoints of sides ab BC and CA of triangle ABC find the ratio of the areas of triangle DEF in triangle ABC. D E and F are respectively the midpoints of sides ab BC and CA of triangle ABC find the ratio of the areas of triangle DEF [...]
If the area of two similar triangles are equal, prove that they are congruent.
05
Oct
If the area of two similar triangles are equal, prove that they are congruent. If the area of two similar triangles are equal prove that they are congruent. October 5, 2020 Category: Chapter 6 - Triangles , Maths , NCERT Class 10 ,
In Fig. 6.44, ABC and DBC are two triangles on the same base BC. If AD intersects BC at O, show that ar(ABC)/ar(DBC) = AO/DO.
05
Oct
In Fig. 6.44, ABC and DBC are two triangles on the same base BC. If AD intersects BC at O, show that ar(ABC)/ar(DBC) = AO/DO. ABC and DBC are two triangles on the same base BC. If AD intersects BC at O In Fig. 6.44 show that ar(ABC)/ar(DBC) = AO/DO. October 5, 2020 Category: Chapter [...]