Chapter 6 – Triangles
In Fig. 6.29, if PQ || RS, prove that Δ POQ ~ ΔSOR.
05
Oct
In Fig. 6.29, if PQ || RS, prove that Δ POQ ~ ΔSOR. if PQ || RS In Fig. 6.29 prove that Δ POQ ~ ΔSOR. October 5, 2020 Category: Chapter 6 - Triangles , Maths , NCERT Class 10 ,
In Fig. 6.16. PS/SQ = PT/TR and angle PST = angle PRQ. Prove that PQR is an isosceles triangle.
05
Oct
In Fig. 6.16. PS/SQ = PT/TR and angle PST = angle PRQ. Prove that PQR is an isosceles triangle. In Fig. 6.16. PS/SQ = PT/TR and angle PST = angle PRQ. Prove that PQR is an isosceles triangle. October 5, 2020 Category: Chapter 6 - Triangles , Maths , NCERT Class 10 ,
In trapezium ABCD, AB || DC. E and F are points on non-parallel sides AD and BC respectively such that EF || AB. Show that AE/BF = ED/FC.
05
Oct
In trapezium ABCD, AB || DC. E and F are points on non-parallel sides AD and BC respectively such that EF || AB. Show that AE/BF = ED/FC. AB || DC. E and F are points on non-parallel sides AD and BC respectively such that EF || AB. Show that AE/BF = ED/FC. In trapezium [...]
If a line intersects sides AB and AC of a triangle ABC at D and E respectively and is parallel to BC, prove that AD/AB = AE/AC.
05
Oct
If a line intersects sides AB and AC of a triangle ABC at D and E respectively and is parallel to BC, prove that AD/AB = AE/AC. If a line intersects sides AB and AC of a triangle ABC at D and E respectively and is parallel to BC prove that AD/AB = AE/AC. October [...]
Nazima is fly fishing in a stream. The tip of her fishing rod is 1.8 m about the surface of the water and the fly at the end of the string rests on the water 3.6 m away and 2.4 m from a point directly under the tip of the rod. Assuming that her string ( from the tip of her rod to the fly ) is taut, how much string does she have out ( see given figure)? If she pulls the string at the rate of 5 cm per second, what will the horizontal distance of the fly from her after 12 second?
05
Oct
Nazima is fly fishing in a stream. The tip of her fishing rod is 1.8 m about the surface of the water and the fly at the end of the string rests on the water 3.6 m away and 2.4 m from a point directly under the tip of the rod. Assuming that her string [...]
In Fig.6.63,D is a point on side BC of Delta ABC such that (BD)/(CD)=(AB)/(AC) .Prove that AD is the bisector of /_BAC.
05
Oct
In Fig.6.63,D is a point on side BC of Delta ABC such that (BD)/(CD)=(AB)/(AC) .Prove that AD is the bisector of /_BAC. D is a point on side BC of Delta ABC such that (BD)/(CD)=(AB)/(AC) .Prove that AD is the bisector of /_BAC. In Fig.6.63 October 5, 2020 Category: Chapter 6 - Triangles , Maths [...]
In fig. 6.62, two chords AB and CD of a circle intersect each other at the point P (when produced) outside the circle. prove that (1) triangle PAC ~ triangle PDB ,(2) PA.PB = PC.PD
05
Oct
In fig. 6.62, two chords AB and CD of a circle intersect each other at the point P (when produced) outside the circle. prove that (1) triangle PAC ~ triangle PDB ,(2) PA.PB = PC.PD (2) PA.PB = PC.PD In fig. 6.62 two chords AB and CD of a circle intersect each other at the [...]
In Fig. 6.61, two chords AB and CD intersect each other at the point P. Prove that: (1) triangle APC ~ triangle DPB () AP. PB = CP.DP
05
Oct
In Fig. 6.61, two chords AB and CD intersect each other at the point P. Prove that: (1) triangle APC ~ triangle DPB () AP. PB = CP.DP In Fig. 6.61 two chords AB and CD intersect each other at the point P. Prove that: (1) triangle APC ~ triangle DPB () AP. PB = [...]
Prove that the sum of the squares of the diagonals of parallelogram is equal to the sum of the squares of its sides.
05
Oct
Prove that the sum of the squares of the diagonals of parallelogram is equal to the sum of the squares of its sides. Prove that the sum of the squares of the diagonals of parallelogram is equal to the sum of the squares of its sides. October 5, 2020 Category: Chapter 6 - Triangles , [...]
In Fig. 6.60 , AD is a median of a triangle ABC and AM⊥BC . Prove that (i) AC^2 = AD^2 + BC⋅DM + (2/BC)^2
05
Oct
In Fig. 6.60 , AD is a median of a triangle ABC and AM⊥BC . Prove that (i) AC^2 = AD^2 + BC⋅DM + (2/BC)^2 AD is a median of a triangle ABC and AM⊥BC . Prove that (i) AC^2 = AD^2 + BC⋅DM + (2/BC)^2 In Fig. 6.60 October 5, 2020 Category: Chapter 6 [...]