N Awasthi Physical Chemistry
5 litre vessel contains 2 moles of each of gases A and B at equilibrium. If 1 mole each of A and B are removed. Calculate KC for the reaction A(g)⇔B(g)
12
Nov
5 litre vessel contains 2 moles of each of gases A and B at equilibrium. If 1 mole each of A and B are removed. Calculate KC for the reaction A(g)⇔B(g) 5 litre vessel contains 2 moles of each of gases A and B at equilibrium. If 1 mole each of A and B are [...]
For the reaction A(g) ⇌ B(g) kc = 10 B(g) ⇌ C(g) kc = 2 C(g) ⇌ D(g) kc = 0.001 calculate kc for the reaction D(g) ⇌ A(g).
12
Nov
For the reaction A(g) ⇌ B(g) kc = 10 B(g) ⇌ C(g) kc = 2 C(g) ⇌ D(g) kc = 0.001 calculate kc for the reaction D(g) ⇌ A(g). For the reaction A(g) ⇌ B(g) kc = 10 B(g) ⇌ C(g) kc = 2 C(g) ⇌ D(g) kc = 0.001 calculate kc for the reaction [...]
In a gaseous reaction A+2B⇔2C+D the initial concentration of B was 1.5 times that of A. At equilibrium the concentration of A and D were equal. Calculate the equilibrium constant KC.
12
Nov
In a gaseous reaction A+2B⇔2C+D the initial concentration of B was 1.5 times that of A. At equilibrium the concentration of A and D were equal. Calculate the equilibrium constant KC. In a gaseous reaction A+2B⇔2C+D the initial concentration of B was 1.5 times that of A. At equilibrium the concentration of A and D [...]
Calculate partial pressure of B at equilibrium in the following equilibrium A(s)⇔B(g)+2C(g),Kp=32atm^3.
12
Nov
Calculate partial pressure of B at equilibrium in the following equilibrium A(s)⇔B(g)+2C(g),Kp=32atm^3. Calculate partial pressure of B at equilibrium in the following equilibrium A(s)⇔B(g)+2C(g) Kp=32atm^3. November 12, 2020 Category: Chapter 5 - Chemical Equilibrium (Level 1 and Level 2) , N Awasthi Physical Chemistry ,
If 50% of CO2 converts to CO at the following equilibrium : 1/2C(s)+1/2CO2(g)⇔CO(g) and the equilibrium pressure is 12 atm Calculate KP.
12
Nov
If 50% of CO2 converts to CO at the following equilibrium : 1/2C(s)+1/2CO2(g)⇔CO(g) and the equilibrium pressure is 12 atm Calculate KP. If 50% of CO2 converts to CO at the following equilibrium : 1/2C(s)+1/2CO2(g)⇔CO(g) and the equilibrium pressure is 12 atm Calculate KP. November 12, 2020 Category: Chapter 5 - Chemical Equilibrium (Level 1 [...]
N2(g) and H2(g) are allowed to react in closed vessel in given temperature and pressure for the formation of NH3(g) N2(g) + 3H2(g) ⇌ 2NH2(g) + 22.4 kcal. If He(g) is added at equilibrium at constant pressure then which is/are correct ?
12
Nov
N2(g) and H2(g) are allowed to react in closed vessel in given temperature and pressure for the formation of NH3(g) N2(g) + 3H2(g) ⇌ 2NH2(g) + 22.4 kcal. If He(g) is added at equilibrium at constant pressure then which is/are correct ? Calculate the reaction given below in which cases will the reaction proceed toward [...]
Heating a2 group metal carbonate leads to decompostion as : BaCo3(s) ⇌ BaO(s) + CO2(g)
12
Nov
Heating a2 group metal carbonate leads to decompostion as : BaCo3(s) ⇌ BaO(s) + CO2(g) Heating a2 group metal carbonate leads to decompostion as : BaCo3(s) ⇌ BaO(s) + CO2(g) November 12, 2020 Category: Chapter 5 - Chemical Equilibrium (Level 1 and Level 2) , N Awasthi Physical Chemistry ,
Increase in the pressure for the following equilibrium results in the : H2O(l) ⇌ H2O(g)
12
Nov
Increase in the pressure for the following equilibrium results in the : H2O(l) ⇌ H2O(g) Increase in the pressure for the following equilibrium results in the : H2O(l) ⇌ H2O(g) November 12, 2020 Category: Chapter 5 - Chemical Equilibrium (Level 1 and Level 2) , N Awasthi Physical Chemistry ,
For a reaction: Cl2 (g) + 3F2(g) ⇌ 2ClF3(g); ΔH = −329 kJ, dissociation of CIF3(g) will be favoured by :
12
Nov
For a reaction: Cl2 (g) + 3F2(g) ⇌ 2ClF3(g); ΔH = −329 kJ, dissociation of CIF3(g) will be favoured by : dissociation of CIF3(g) will be favoured by : For a reaction: Cl2 (g) + 3F2(g) ⇌ 2ClF3(g); ΔH = −329 kJ November 12, 2020 Category: Chapter 5 - Chemical Equilibrium (Level 1 and Level [...]
For the reaction PCI5(g) ⇌ PCI3(g), the forward reaction at constant temperature is favoured by:
12
Nov
For the reaction PCI5(g) ⇌ PCI3(g), the forward reaction at constant temperature is favoured by: For the reaction PCI5(g) ⇌ PCI3(g) the forward reaction at constant temperature is favoured by: November 12, 2020 Category: Chapter 5 - Chemical Equilibrium (Level 1 and Level 2) , N Awasthi Physical Chemistry ,