Chapter 5 – Chemical Equilibrium (Level 1 and Level 2)
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The gas A2 in the left flask allowed to react with gas B2 present in right flask as A2(g)+B2(g)⇔2AB(g),Kc=4 at 27^∘C. What is the concentration of AB when equilibrium is established ?
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The gas A2 in the left flask allowed to react with gas B2 present in right flask as A2(g)+B2(g)⇔2AB(g),Kc=4 at 27^∘C. What is the concentration of AB when equilibrium is established ? Kc=4 at 27^∘C. What is the concentration of AB when equilibrium is established ? The gas A2 in the left flask allowed to [...]
One mole of N2 (g) is mixed with 2 moles of H 2(g) in a 4 litre vessel. If 50% of N2(g) is converted to H2(g) by the following reaction : N2 (g)+3H2(g)⇌2NH3 (g) What will be the value of Kc for the following equilibrium? NH3 (g)⇌ 2/1 N2 (g) + 2/3 H2 (g)
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Nov
One mole of N2 (g) is mixed with 2 moles of H 2(g) in a 4 litre vessel. If 50% of N2(g) is converted to H2(g) by the following reaction : N2 (g)+3H2(g)⇌2NH3 (g) What will be the value of Kc for the following equilibrium? NH3 (g)⇌ 2/1 N2 (g) + 2/3 H2 (g) [...]
The following equilibrium constants were determined at 1120K: 2CO(g)⇔C(s)+CO2(g),,Kp1=10−114atm−1 CO(g)+Cl2(g)⇔COCl2(g),,Kp2=6×10−3atm−1 What is the equilibrium constant Kc for the following reaction at 1120K: C(s)+CO2(g)+2Cl2(g)⇔2COCl2(g)
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Nov
The following equilibrium constants were determined at 1120K: 2CO(g)⇔C(s)+CO2(g),,Kp1=10−114atm−1 CO(g)+Cl2(g)⇔COCl2(g),,Kp2=6×10−3atm−1 What is the equilibrium constant Kc for the following reaction at 1120K: C(s)+CO2(g)+2Cl2(g)⇔2COCl2(g) Kp1=10−114atm−1 CO(g)+Cl2(g)⇔COCl2(g) Kp2=6×10−3atm−1 What is the equilibrium constant Kc for the following reaction at 1120K: C(s)+CO2(g)+2Cl2(g)⇔2COCl2(g) The following equilibrium constants were determined at 1120K: 2CO(g)⇔C(s)+CO2(g) November 11, 2020 Category: Chapter 5 - [...]
The standard free energy change of a reaction is ΔG∘=−115 kJ mol^-1 at 298 K. Calculate the the value of log10 Kp (R=8.314 jK^−1mol^−1)
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Nov
The standard free energy change of a reaction is ΔG∘=−115 kJ mol^-1 at 298 K. Calculate the the value of log10 Kp (R=8.314 jK^−1mol^−1) The standard free energy change of a reaction is ΔG∘=−115 kJ mol^-1 at 298 K. Calculate the the value of log10 Kp (R=8.314 jK^−1mol^−1) November 11, 2020 Category: Chapter 5 - [...]
Solid Ca(HCO3) 2 decomposes as Ca(HCO3)2 (s)⇌CaCO3(s)+CO2 (g)+H2 O(g) If the total pressure is 0.2 bar at 420K what is the standard free energy change for given reaction (ΔrG^o )?
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Solid Ca(HCO3) 2 decomposes as Ca(HCO3)2 (s)⇌CaCO3(s)+CO2 (g)+H2 O(g) If the total pressure is 0.2 bar at 420K what is the standard free energy change for given reaction (ΔrG^o )? Solid Ca(HCO3) 2 decomposes as Ca(HCO3)2 (s)⇌CaCO3(s)+CO2 (g)+H2 O(g) If the total pressure is 0.2 bar at 420K what is the standard free [...]
For the reaction at 300K A(g)⇔V(g)+S(g) ΔrH∘=−30kJ/mol, ΔrS∘=−0.1Kj.k^−1.mol^−1 What is the value of equilibrium constant ?
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Nov
For the reaction at 300K A(g)⇔V(g)+S(g) ΔrH∘=−30kJ/mol, ΔrS∘=−0.1Kj.k^−1.mol^−1 What is the value of equilibrium constant ? For the reaction at 300K A(g)⇔V(g)+S(g) ΔrH∘=−30kJ/mol ΔrS∘=−0.1Kj.k^−1.mol^−1 What is the value of equilibrium constant ? November 11, 2020 Category: Chapter 5 - Chemical Equilibrium (Level 1 and Level 2) , N Awasthi Physical Chemistry ,
A plot of Gibbs energy of a reaction mixture against the extent of the reaction is:
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A plot of Gibbs energy of a reaction mixture against the extent of the reaction is: A plot of Gibbs energy of a reaction mixture against the extent of the reaction is: November 11, 2020 Category: Chapter 5 - Chemical Equilibrium (Level 1 and Level 2) , N Awasthi Physical Chemistry ,
The value of ΔG degree for a reaction in aqueous phase having kc = 1, would be:
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The value of ΔG degree for a reaction in aqueous phase having kc = 1, would be: The value of ΔG degree for a reaction in aqueous phase having kc = 1 would be November 11, 2020 Category: Chapter 5 - Chemical Equilibrium (Level 1 and Level 2) , N Awasthi Physical Chemistry ,
When 1 mole of pure ethyl alcohol (C2H5OH) is mixed with 1 mole of acetic acid at 25∘C. the equilibrium mixture contains 2/3 mole each of ester and water C2h5OH(l)+CH3COOH(l)⇔CH3COOC2H5(l)+H2O(l) The ΔG∘ for the reaction at 298K is :
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When 1 mole of pure ethyl alcohol (C2H5OH) is mixed with 1 mole of acetic acid at 25∘C. the equilibrium mixture contains 2/3 mole each of ester and water C2h5OH(l)+CH3COOH(l)⇔CH3COOC2H5(l)+H2O(l) The ΔG∘ for the reaction at 298K is : The most stable oxides of nitrogen will be : November 11, 2020 Category: Chapter 5 - [...]
The most stable oxides of nitrogen will be :
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The most stable oxides of nitrogen will be : The most stable oxides of nitrogen will be : November 11, 2020 Category: Chapter 5 - Chemical Equilibrium (Level 1 and Level 2) , N Awasthi Physical Chemistry ,