Part 1

A simple harmonic motion is represented by x(t)=sin^2ωt − 2cos^2ωt. The angular frequency of oscillation is given by A simple harmonic motion is represented by x(t)=sin^2ωt − 2cos^2ωt. The angular frequency of oscillation is given by November 7, 2020 Category: Chapter 11 - SHM , MTG NEET Physics , Part 1 ,

The equation of motion of a particle executing simple harmonic motion is a + 16π^2x = 0 In this equation, a is the linear acceleration in m/s^2 of the particle at a displacement x in meter. The time period in simple harmonic motion is a is the linear acceleration in m/s^2 of the particle at [...]

A particle executes SHM of type x=asinωt. It takes time t1 from x = 0 to x = 2/a and t2 ​from x = 2/a to x = a. The ratio of t1 ​: t2 ​will be: the-function-sinwt-coswt-represents-a-a-shm-with-a-period-π-ω-duplicate-3 November 7, 2020 Category: Chapter 11 - SHM , MTG NEET Physics , Part 1 ,

Let x = xmcos(wt+φ). At t = 0, x = xm. If time period is T, what is the time taken to reach x = xm/2 ? Let x = xmcos(wt+φ). At t = 0 what is the time taken to reach x = xm/2 ? x = xm. If time period is T November [...]

The function sinwt – coswt represents (a) a SHM with a period π/ω. The function sinwt - coswt represents (a) a SHM with a period π/ω. November 7, 2020 Category: Chapter 11 - SHM , MTG NEET Physics , Part 1 ,

A particle is executing simple harmonic motion of amplitude 5 cm and period 6 s. How long will it take to move from one end of its path on one side of mean position to a position 2.5 cm on the same side of the mean position? the frequency of a tuning fork When temperature [...]

The displacement of a particle executing SHM is given by x = 0.25 sin 200t cm where t is in seconds. Calculate the maximum speed of the particle is The displacement of a particle executing SHM is given by x = 0.25 sin 200t cm where t is in seconds. Calculate the maximum speed of [...]

The maximum velocity of a particle, executing simple harmonic motion with an amplitude 7 mm, is 4.4 m/s. The time period of oscillation is executing simple harmonic motion with an amplitude 7 mm is 4.4 m/s. The time period of oscillation is The maximum velocity of a particle November 7, 2020 Category: Chapter 11 - [...]

A point particle oscillates along the x-axis according to the law x = x0 cos(ωt − 4/π ). If the acceleration of the particle is written as a = A cos(ωt + δ), then A point particle oscillates along the x-axis according to the law x = x0 cos(ωt − 4/π ). If the acceleration [...]

A particle executes linear simple harmonic motion with an amplitude of 2 cm . When the particle is at 1 cm from the mean position the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is the frequency of a tuning fork When temperature increase November 7, [...]